ÌâÄ¿ÄÚÈÝ

ÈçͼËùʾ£¬ÔÚÏà¾àL="0.5" mµÄÁ½Ìõˮƽ·ÅÖÃÎÞÏÞ³¤µÄ½ðÊôµ¼¹ìÉÏ£¬·ÅÖÃÁ½¸ù½ðÊô°ôabºÍcd£¬Á½°ôµÄÖÊÁ¿¾ùΪm="0.1" kg£¬µç×è¾ùΪR="3" ¦¸£¬Õû¸ö×°Öô¦ÓÚÎÞÏÞ´ó¡¢ÊúÖ±ÏòϵÄÔÈÇ¿´Å³¡ÖУ¬´Å¸ÐӦǿ¶ÈB="1" T£¬µ¼¹ìµç×輰Ħ²ÁÁ¦¾ù²»¼Æ.´Ót=0ʱ¿Ì¿ªÊ¼£¬ÓÃһˮƽÏòÓҵĺãÁ¦F×÷ÓÃÓÚab°ôÉÏ£¬Ê¹ab°ô´Ó¾²Ö¹¿ªÊ¼Ô˶¯£¬¾­¹ýt="4" s£¬»Ø·´ïµ½ÁËÎȶ¨×´Ì¬£¬´Ëºó»Ø·ÖеçÁ÷±£³Ö0.6 A²»±ä.ÇóµÚ4 sʱ

(1)cd°ôµÄ¼ÓËٶȴóС£»
(2)ab°ôÓëcd°ôµÄËÙ¶ÈÖ®²î£»
(3)ab°ôµÄËٶȴóС.
(1)3 m/s2  (2)7.2 m/s  (3)15.6 m/s
(1)Ecd="BLI=1¡Á0.5¡Á0.6" N="0.3" N
cd°ôµÄ¼ÓËÙ¶È="3" m/s2.
(2)IR×Ü=BLvab-BLvcd=BL¡¤¦¤v
´úÈëÊýÖµ£¬½âµÃ¦¤v="7.2" m/s£¬
»Ø·´ïµ½Îȶ¨×´Ì¬£¬Á½°ôÓй²Í¬µÄ¼ÓËÙ¶È.
(3)¶ÔÓÚab°ô£ºF-Fcd=ma
½âµÃF="0.6" N
¸ù¾Ý¶¯Á¿¶¨Àí£¬¶ÔÓÚab°ô£º
(F-BL)t=mvab£»
¶ÔÓÚcd°ô£ºBLt=mvcd
ÆäÖÐIΪƽ¾ùµçÁ÷£¬ÓÉÒÔÉÏÁ½Ê½µÃ
Ft=mvab+mvcd
´úÈëÊýÖµ£¬µÃvab="15.6" m/s.
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø