题目内容
如图所示,木块A的右侧为光滑曲面,曲面下端极薄,其质量
,原来静止在光滑的水平面上,质量
的小球B以v=2m/s的速度从右向左做匀速直线运动中与木块A发生相互作用,则B球沿木块A的曲面向上运动中可上升的最大高度(设B球不能飞出去)是( )
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250052394091905.jpg)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825005239378685.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825005239393685.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250052394091905.jpg)
A.0.40m | B.0.20m |
C.0.10m | D.0.5m |
C
试题分析: A、B组成的系统在水平方向动量守恒,以B的初速度方向为正方向,由动量守恒定律得:
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825005239424841.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250052394401359.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825005239456547.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
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