题目内容
两颗人造卫星A、B绕地球做圆周运动,周期之比为TA∶TB=1∶8,则轨道半径之比和运动速率之比分别为( ).
A.RA∶RB=4∶1,vA∶vB=1∶2
B.RA∶RB=4∶1,vA∶vB=2∶1
C.RA∶RB=1∶4,vA∶vB=1∶2
D.RA∶RB=1∶4,vA∶vB=2∶1
A.RA∶RB=4∶1,vA∶vB=1∶2
B.RA∶RB=4∶1,vA∶vB=2∶1
C.RA∶RB=1∶4,vA∶vB=1∶2
D.RA∶RB=1∶4,vA∶vB=2∶1
D
由开普勒第三定律得
=
,则
=
,又由v=
,可知
=
,故D选项正确.
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003718664538.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003718695536.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003718711456.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003718726303.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003718742580.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003718773446.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003718789345.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
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