ÌâÄ¿ÄÚÈÝ

(8·Ö£©ÓÃË«·ì¸ÉÉæ²â¹âµÄ²¨³¤¡£ÊµÑé×°ÖÃÈçͼ£¨¼×£©Ëùʾ£¬ÒÑÖªµ¥·ìÓëË«·ì¼äµÄ¾àÀëL1=100mm£¬Ë«·ìÓëÆÁµÄ¾àÀëL2=700mm£¬Ë«·ì¼ä¾àd=0.25mm¡£ÓòâÁ¿Í·À´²âÁ¿ÁÁÎÆÖÐÐĵľàÀë¡£²âÁ¿Í·ÓÉ·Ö»®°å¡¢Ä¿¾µ¡¢ÊÖÂֵȹ¹³É£¬×ª¶¯ÊÖÂÖ£¬Ê¹·Ö»®°å×óÓÒÒƶ¯£¬È÷ֻ®°åµÄÖÐÐÄ¿ÌÏ߶Ô×¼ÁÁÎƵÄÖÐÐÄ£¨Èçͼ£¨ÒÒ£©Ëùʾ£©£¬¼ÇÏ´ËʱÊÖÂÖÉϵĶÁÊý£¬×ª¶¯²âÁ¿Í·£¬Ê¹·Ö»®°åÖÐÐÄ¿ÌÏ߶Ô×¼ÁíÒ»ÌõÁÁÎƵÄÖÐÐÄ£¬¼ÇÏ´ËʱÊÖÂÖÉϵĶÁÊý¡£

¢Ù·Ö»®°åµÄÖÐÐÄ¿ÌÏß·Ö±ð¶Ô×¼µÚ1ÌõºÍµÚ4ÌõÁÁÎƵÄÖÐÐÄʱ£¬ÊÖÂÖÉϵĶÁÊýÈçͼ£¨±û£©Ëùʾ£¬Ôò¶Ô×¼µÚ1Ìõʱ¶ÁÊýx1=_______mm¡¢¶Ô×¼µÚ4Ìõʱ¶ÁÊýx2=_______mm
¢Úд³ö¼ÆË㲨³¤¦ËµÄ±í´ïʽ£¬¦Ë=_________£¨Ó÷ûºÅ±íʾ£©£¬¦Ë=_____nm£¨±£ÁôÈýλÓÐЧÊý×Ö£©

¢Ù  2.190£»7.868£»¢Ú £»667.

½âÎöÊÔÌâ·ÖÎö£º¢Ù ¶Ô×¼µÚ1Ìõʱ¶ÁÊýx1="2mm+0.01mm¡Á19.0=2.190" mm£»¶Ô×¼µÚ4Ìõʱ¶ÁÊýx2=7.5mm+0.01mm¡Á36.8=7.868mm£»¢Ú ÒòΪx2-x1=3¡÷x£¬¸ù¾Ý¿ÉÖª£¬£¬´úÈëÊý¾Ý¿ÉµÃ£º¡£
¿¼µã£ºË«·ì¸ÉÉæ²â¹âµÄ²¨³¤

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

ijʵÑéС×éÀûÓÃͼ¼×ËùʾµÄʵÑé×°ÖÃ̽¾¿ºãÁ¦×ö¹¦Ó붯ÄܸıäÁ¿µÄ¹Øϵ¡£Ëù¹ÒíÀÂëÖÊÁ¿Îªm£¬ÖØÁ¦¼ÓËÙ¶ÈΪg£¬ÉèС³µÖÊÁ¿ÎªM£¨Ô¼ÎªíÀÂëÖÊÁ¿µÄ2¡«3±¶£©¡£

¢ÙƽºâС³µËùÊÜ×èÁ¦µÄ²Ù×÷ÈçÏ£ºÈ¡ÏÂíÀÂ룬°Ñľ°å²»´ø»¬ÂÖµÄÒ»¶Ëµæ¸ß£»½Óͨ´òµã¼ÆʱÆ÷µçÔ´£¬ÇáÍÆС³µ£¬ÈÃС³µÍÏ×ÅÖ½´øÔ˶¯£¬Èç¹û´ò³öµÄÖ½´øÈçͼÒÒËùʾ£¬ÔòÓ¦Êʵ±____________£¨Ñ¡Ìî¡°Ôö´ó¡±»ò¡°¼õС¡±£©Ä¾°åµÄÇã½Ç£¬Ö±µ½Ö½´øÉÏ´ò³öµÄµã¼£____________Ϊֹ¡£
¢ÚÔÚÖ½´øÉÏÑ¡È¡ÏȺó´òÓ¡µÄA¡¢BÁ½¼ÆÊýµã£¬ÉèA¡¢BÁ½¼ÆÊýµã¼äµÄ¾àÀëΪd£¬´òÕâÁ½µãʱС³µ¶ÔÓ¦µÄËٶȷֱðΪvA¡¢vB£¬Ôò±¾ÊµÑéÐèÑéÖ¤±í´ïʽ_____________________ÔÚÎó²î·¶Î§ÄÚÊÇ·ñ³ÉÁ¢¡£   
¢Ûij´ÎʵÑéÕýÈ·²Ù×÷ºó£¬¸ù¾Ý²âµÃµÄʵÑéÊý¾ÝÃè»æ³öµÄv2¡ªsͼÏßÈçͼ±ûËùʾ£¬ÆäÖкá×ø±êsΪС³µ·¢ÉúµÄλÒÆ£¬×Ý×ø±êv2ΪС³µÔ˶¯ËٶȴóСµÄƽ·½¡£ÈôÒÑ֪ͼÖÐÖ±ÏßµÄбÂÊΪk£¬ÔÚ×ÝÖáÉϵĽؾàΪb£¬Óɴ˿ɵÃs=0ʱС³µµÄËٶȴóС_______£¬Ð¡³µÖÊÁ¿M=___________¡££¨ÓÃÌâÖÐËù¸øÒÑÖªÁ¿×Öĸ±íʾ£©

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø