题目内容
A、B是一条电场线上的两点,若在A点释放一初速为零的电子,电子仅受电场力作用,并沿电场线从A运动到B,其速度随时间变化的规律如图2所示.设A、B两点的电场强度分别为EA、EB,电势分别为UA、UB,则( )
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250013140701209.png)
A.EA = EB. B.EA<EB
C. UA = UB D.UA<UB .
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250013140701209.png)
A.EA = EB. B.EA<EB
C. UA = UB D.UA<UB .
AD
试题分析:由图可知,电子做初速度为零的匀加速直线运动,由牛顿第二定律可知,电子受到恒定的电场力作用,即电场为匀强电场,有
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825001314086500.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825001314101598.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825001314117521.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
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