题目内容
(10分)如图所示,一簇平行线为未知方向的匀强电场的电场线,沿与此平行线成60°角的方向,把1×10-3C的负电荷从A点移到B点,电场力做功为2×10-3J,A、B间距为2cm
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241448596082197.png)
求(1)匀强电场的场强
(2)若B点电势为1V,则A点电势为多大
(3)电子处于B点时,具有的电势能是多少eV,它从A点移到B点,动能增加多少eV.
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241448596082197.png)
求(1)匀强电场的场强
(2)若B点电势为1V,则A点电势为多大
(3)电子处于B点时,具有的电势能是多少eV,它从A点移到B点,动能增加多少eV.
(1)200V/m(2)-1V(3)2eV
试题分析:(1)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824144900014917.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241449001701371.png)
(2)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824144900217787.png)
(3)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824144900419738.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824144900466899.png)
点评:在由电场力做功求解电势差的时候要注意功W和电势差U的下脚标
![](http://thumb2018.1010pic.com/images/loading.gif)
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