题目内容
如图所示,表示五个共点力的有向线段恰分别构成正六边形的两条邻边和三条对角线.已知F1=10 N,这五个共点力的合力大小为( )
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241321156752518.jpg)
图2-5-13
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241321156752518.jpg)
图2-5-13
A.0 | B.30 N |
C.60 N | D.90 N |
C
:选C.先把F1、F4合成,则F14=F3,再把F2、F5合成,则F25=F3,由几何关系可知F3=2F1=20 N,所以F合=3F3=60 N.
![](http://thumb2018.1010pic.com/images/loading.gif)
练习册系列答案
相关题目
题目内容
A.0 | B.30 N |
C.60 N | D.90 N |