题目内容
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A.表中a是84,b是206
B.x是β衰变,放出电子,电子是由中子转变为质子时产生的
C.y是β衰变,放出电子,电子是由中子转变为质子时产生的
D.从
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【答案】分析:α衰变的过程中电荷数少2,质量数少4,β衰变的过程中电荷数多1,质量数不变.
解答:解:A、
→
质量数少4,知发生了一次α衰变,则电荷数少2,所以a=84,
→
发生了一次α衰变,则b=206.故A正确.
B、
→
发生了7次α衰变,5次β衰变.故B错误.
C、
→
发生了β衰变,电子有中子转变为质子时产生的.故C正确.
D、从
U衰变成
Pb质量数少32,知发生8次α衰变,6次β衰变.故D错误.
故选AC.
点评:解决本题的关键知道α衰变、β衰变的实质,知道在衰变的过程中电荷数守恒、质量数守恒.
解答:解:A、
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B、
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C、
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D、从
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故选AC.
点评:解决本题的关键知道α衰变、β衰变的实质,知道在衰变的过程中电荷数守恒、质量数守恒.
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