ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿Ò»¸ù¾ùÔȵÄϸ³¤¿ÕÐĽðÊôÔ²¹Ü£¬Æäºá½ØÃæÈçͼ¼×Ëùʾ£¬³¤¶ÈΪL £¬µç×èRԼΪ5¦¸£¬ÕâÖÖ½ðÊôµÄµç×èÂÊΪ¦Ñ£¬Òò¹ÜÏßÄÚ¾¶Ì«Ð¡ÎÞ·¨Ö±½Ó²âÁ¿£¬Ä³Í¬Ñ§Éè¼ÆÏÂÁÐʵÑé·½°¸¾¡¿ÉÄܾ«È·²â¶¨ËüµÄÄÚ¾¶d£»

(1)ÓÃÂÝÐý²â΢Æ÷²âÁ¿½ðÊô¹ÜÏßÍ⾶D£¬Í¼ÒÒΪÂÝÐý²â΢Æ÷УÁãʱµÄʾÊý£¬ÓøÃÂÝÐý²â΢Æ÷²âÁ¿µÄ¹ÜÏßÍ⾶¶ÁÊýΪ5.200mm£¬ÔòËù²â½ðÊô¹ÜÏßÍ⾶D=_______mm£®

(2)Ϊ²âÁ¿½ðÊô¹ÜÏߵĵç×èR£¬È¡Á½½Ú¸Éµç³Ø£¨ÄÚ×è²»¼Æ£©¡¢¿ª¹ØºÍÈô¸Éµ¼Ïß¼°ÏÂÁÐÆ÷²Ä£º

A£®µçÁ÷±í0¡«0.6A£¬ÄÚ×èÔ¼0.05¦¸

B£®µçÁ÷±í0¡«3A£¬ÄÚ×èÔ¼0.01¦¸

C£®µçѹ±í0¡«3V£¬ÄÚ×èÔ¼10k¦¸

D£®µçѹ±í0¡«15V£¬ÄÚ×èÔ¼50k¦¸

E£®»¬¶¯±ä×èÆ÷£¬0¡«10¦¸£¨¶î¶¨µçÁ÷Ϊ0.6A£©

F£®»¬¶¯±ä×èÆ÷£¬0¡«100¦¸£¨¶î¶¨µçÁ÷Ϊ0.3A£©

Ϊ׼ȷ²â³ö½ðÊô¹ÜÏß×èÖµ£¬µçÁ÷±íӦѡ_______£¬µçѹ±íӦѡ______£¬»¬¶¯±ä×èÆ÷Ӧѡ_______(ÌîÐòºÅ)

(3)Èçͼ±ûËùʾ£¬Ç밴ʵÑéÒªÇóÓñʴúÏß½«ÊµÎïͼÖеÄÁ¬Ïß²¹³äÍêÕû_______£®

(4)¸ù¾ÝÒÑÖªµÄÎïÀíÁ¿£¨³¤¶ÈL¡¢µç×èÂʦѣ©ºÍʵÑéÖвâÁ¿µÄÎïÀíÁ¿£¨µçѹ±í¶ÁÊýU¡¢µçÁ÷±í¶ÁÊýI¡¢½ðÊô¹ÜÏßÍ⾶D£©£¬Ôò½ðÊô¹ÜÏßÄÚ¾¶±í´ïʽd£½______________

¡¾´ð°¸¡¿5.167 A C E

¡¾½âÎö¡¿

(1)[1]ÂÝÐý²â΢Æ÷УÁãʱµÄʾÊý

3.3¡Á0.01mm=0.033mm

ÂÝÐý²â΢Æ÷²âÁ¿µÄ¹ÜÏßÍ⾶¶ÁÊýΪ5.200mm£¬ÔòËù²â½ðÊô¹ÜÏßÍ⾶

D=5.200-0.033mm=5.167mm£®

(2)[2]Á½½Úеĸɵç³Øµç¶¯ÊÆΪ3V£¬Òò´Ëµçѹ±íÑ¡Ôñ3 VµÄÁ¿³Ì£¬¼´ÎªC£»
[3]ÒòΪµçÁ¿ÖÐ×î´óµçÁ÷´óԼΪ

ΪÁ˲âÁ¿µÄ¾«È·£¬µçÁ÷±íӦѡÔñA£¬

[4]»¬¶¯±ä×èÆ÷²ÉÓÃÏÞÁ÷ʽ½Ó·¨£¬ÒòΪ´ý²âµç×è½ÏС£¬ËùÒÔ»¬¶¯±ä×èÆ÷Ñ¡ÔñE£®
(3) [5]ÓÉÓÚ´ý²âµç×èµÄƽ·½Ð¡ÓÚµçѹ±íÓëµçÁ÷±íÄÚ×èµÄ³Ë»ý£¬ÊôÓÚСµç×裬ËùÒÔµçÁ÷±í²ÉÓÃÍâ½Ó·¨£¬Á¬½Ó»¬¶¯±ä×èÆ÷µÄ»¬Æ¬½ÓÍ·´íÎó£¬Ó¦¸ÃÔÚ½ÓÏßÖù£»


(4)[6]¸ÃʵÑéÐèÒª²âÁ¿¿ÕÐĽðÊô¹ÜµÄÄÚ¾¶£¬Í¨¹ýÅ·Ä·¶¨Âɲâ³öµç×èµÄ´óС£¬½áºÏµç×趨Âɲâ³öºá½ØÃæ»ý£¬´Ó¶ø¸ù¾ÝÍ⾶Çó³öÄÚ¾¶µÄ´óС£®¹ÊËùÐè²âÁ¿µÄÎïÀíÁ¿Îª½ðÊô¹ÜµÄ³¤¶ÈL¡¢½ðÊô¹ÜµÄÍ⾶D¡¢¼ÓÔÚ¹ÜÁ½¶ËµÄµçѹU¡¢Í¨¹ý¹ÜµÄµçÁ÷Ç¿¶ÈI£®

¾ÝÅ·Ä·¶¨Âɵã¬

£¬ÓÖ £¬Ôò £¬ÒòΪ

½âµÃ:

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø