题目内容
如图所示,如图所示,一根长为L=1.0m,质量为m=0.1kg的导线AB,用软导线悬挂在方向水平的磁感应强度为B=1T的磁场中,现要使悬线拉力为零,则:
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241608173674849.jpg)
(1)AB导线通电方向怎样?
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824160817476163.png)
(2)电流强度是多大? (重力加速度g取10m/s2)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241608173674849.jpg)
(1)AB导线通电方向怎样?
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824160817476163.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824160817726145.png)
(1)A指向B(2)1A
试题分析:1)A指向B(或向右)……………………4分
(2)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824160817991590.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824160818334775.png)
点评:根据悬线拉力为零判断出安培力的方向,然后根据左手定则,即可判断出电流方向.
![](http://thumb2018.1010pic.com/images/loading.gif)
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