题目内容
A、B两电阻串联后接入电源,改变电源的电压,测得电阻A、B的伏安特性曲线如图7所示,则电阻RA、RB和功率PA、PB的关系是
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241535218115427.png)
A.RA>RB B.RA<RB
C.PA>PB D.PA<PB
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241535218115427.png)
A.RA>RB B.RA<RB
C.PA>PB D.PA<PB
BD
试题分析:由图可知,A的斜率大于B的斜率,因图线的斜率为电阻的倒数,所以得到
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824153521889513.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824153521982478.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824153522076494.png)
点评:学生会分析I-U图像的斜率表示的是电阻的倒数,解题时要看清坐标轴表示的物理量。
![](http://thumb2018.1010pic.com/images/loading.gif)
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