题目内容
如图所示,平行实线代表电场线,但未标明方向,一个带电量为-10-6 C的微粒在电场中仅受电场力作用,当它从A点运动到B点时动能减少了10-5 J,则该电荷运动轨迹应为虚线________(选“1”或 “2”);若A点的电势为-10 V,则B点电势为 V 。![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241347361921306.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241347361921306.png)
1,(2分) -20(2分)
从A点运动到B点时动能减少,电场力做负功,电场力方向向左,因为该粒子为负电荷,电场线向右,电场力方向指向曲线的凹侧,轨迹为虚线1,由
,![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241347363641036.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241347362861287.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241347363641036.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
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