ÌâÄ¿ÄÚÈÝ

£¨1£©Ä³ÊÔÑéС×éÀûÓÃÀ­Á¦´«¸ÐÆ÷À´Ñé֤ţ¶ÙµÚ¶þ¶¨ÂÉ£¬ÊµÑé×°ÖÃÈçͼ£®ËûÃǽ«À­Á¦´«¸ÐÆ÷¹Ì¶¨ÔÚС³µÉÏ£¬Óò»¿ÉÉ쳤µÄϸÏß½«Æäͨ¹ýÒ»¸ö¶¨»¬ÂÖÓë¹³ÂëÏàÁ¬£¬ÓÃÀ­Á¦´«¸ÐÆ÷¼Ç¼С³µÊܵ½µÄÀ­Á¦FµÄ´óС£»Ð¡³µºóÃæ¹Ì¶¨Ò»´òµã¼ÆʱÆ÷£¬Í¨¹ýË©ÔÚС³µÉϵÄÖ½´ø£¬¿É²âÁ¿Ð¡³µÔȼÓËÙÔ˶¯µÄËÙ¶ÈÓë¼ÓËٶȣ®
¢ÙÈô½»Á÷µçµÄƵÂÊΪ50Hz£¬Ôò¸ù¾ÝÏÂͼËù´òÖ½´øµÄ´òµã¼Ç¼£¬Ð¡³µ´Ë´ÎÔ˶¯¾­BµãʱµÄËÙ¶ÈvB______m/s£¬Ð¡³µµÄ¼ÓËÙ¶Èa=______m/s2£®£¨vB¡¢aµÄ½á¹û¾ù±£Áôµ½Ð¡ÊýµãºóÁ½Î»£©
¾«Ó¢¼Ò½ÌÍø

¢ÚÒªÑé֤ţ¶ÙµÚ¶þ¶¨ÂÉ£¬³ýÁËÇ°ÃæÌá¼°µÄÆ÷²Ä¼°ÒѲâ³öµÄÎïÀíÁ¿Í⣬ʵÑéÖл¹ÒªÊ¹ÓÃ______£¨ÌîÒÇÆ÷Ãû³Æ£©À´²âÁ¿³ö______£®£¨ÌîÎïÀíÁ¿Ãû³Æ£©£®
¢ÛÓÉÓÚС³µËùÊÜ×èÁ¦fµÄ´óСÄÑÒÔ²âÁ¿£¬ÎªÁ˾¡Á¿¼õСʵÑéµÄÎó²î£¬Ð辡¿ÉÄܽµµÍС³µËùÊÜ×èÁ¦fµÄÓ°Ï죬ÒÔϲÉÈ¡µÄ´ëÂÃÖбØÒªµÄÊÇ£¨Ë«Ñ¡£©£º______£®
A£®Êʵ±µæ¸ß³¤Ä¾°åÎÞ»¬ÂÖµÄÒ»¶Ë£¬Ê¹Î´¹Ò¹³ÂëµÄС³µ±»ÇáÍƺóÇ¡ÄÜÍÏ×ÅÖ½´øÔÈËÙÏ»¬
B£®Ó¦Ê¹¹³Âë×ÜÖÊÁ¿mԶСÓÚС³µ£¨¼ÓÉÏ´«¸ÐÆ÷£©µÄ×ÜÖÊÁ¿M
C£®¶¨»¬ÂÖµÄÂÖÖáÒª¾¡Á¿¹â»¬
D£®Êʵ±Ôö´ó¹³ÂëµÄ×ÜÖÊÁ¿m
£¨2£©Ä³ÐËȤС×éµÄͬѧÖÆ×÷ÁËÒ»¸ö¡°Ë®¹ûµç³Ø¡±£º½«-ͭƬºÍһпƬ·Ö±ð²åÈëһֻƻ¹ûÄÚ£¬¾Í¹¹³ÉÁËÒ»¸ö¼òµ¥µÄ¡°Ë®¹ûµç³Ø¡±£¬Æäµç¶¯ÊÆԼΪ1.5V£¬ÄÚ×èÔ¼Óм¸°ÙÅ·£®ÏÖÒªÇóÄãÓÃÁ¿³ÌºÏÊʵĵçѹ±í£¨ÄÚ×è½Ï´ó£©¡¢µçÁ÷±í£¨ÄÚ×è½ÏС£©À´²â¶¨Ë®¹ûµç³ØµÄµç¶¯ÊÆEºÍÄÚµç×èr£®
¢Ù±¾ÊµÑéµÄµç·Ӧ¸ÃÑ¡ÔñÏÂÃæµÄͼ¼×»òͼÒÒÖеģº______

¾«Ó¢¼Ò½ÌÍø

¢ÚÈô¸ø³öµÄ»¬¶¯±ä×èÆ÷ÓÐÁ½ÖÖ¹æ¸ñ£ºA£¨0¡«20¦¸£©¡¢B£¨0¡«3k¦¸£©£®±¾ÊµÑéÖÐÓ¦¸ÃÑ¡ÓõĻ¬¶¯±ä×èÆ÷Ϊ£º______ͨµçÇ°Ó¦¸Ã°Ñ±ä×èÆ÷µÄ×èÖµµ÷ÖÁ______£®
¢ÛʵÑéÖвâ³öÁù×飨U£¬I£©µÄÖµ£¬ÔÚU-I×ø±êϵÖÐÃè³öͼ±ûËùʾµÄÁù¸öµã£¬·ÖÎöͼÖеĵ㼣¿ÉµÃ³öË®¹ûµç³ØµÄµç¶¯ÊÆΪE=______V£¬ÄÚµç×èΪr=______¦¸£®£¨¾ù±£Áô3λÓÐЧÊý×Ö£©
¢Ü¸ù¾ÝÄãÔÚ¢ÙÖÐËùÑ¡ÔñµÄµç·À´²âÁ¿µÃ³öµÄµç¶¯ÊÆEºÍÄÚµç×èrµÄ²âÁ¿ÖµÓëÕæʵֵÏà±È£ºµç¶¯ÊÆE______£¬ÄÚµç×èr______£®£¨¾ùÑ¡Ì¡°Æ«´ó¡±¡¢¡°ÏàµÈ¡±»ò¡°Æ«Ð¡¡±£©ÓÉ´ËÔì³ÉµÄʵÑéÎó²îÊôÓÚ______Îó²î£®£¨Ñ¡Ìϵͳ¡±»ò¡°Å¼È»¡±£©
¾«Ó¢¼Ò½ÌÍø
£¨1£©ÓÉͼ¿ÉÖª£¬ÏàÁÚ¼ÆÊýµã¼äµÄʱ¼ä¼ä¸ô£ºt=0.02s¡Á5=0.1s£»
´óÏÂBʱС³µµÄËٶȣºvB=
.
vAC
=
AC
2t
=
8.00
2¡Á0.1
cm/s=40.0cm/s=0.40m/s£»
¼ÓËٶȣºa=
BC-AB
t2
=
(8.00-3.27)-3.27
0£®12
=146cm/s2=1.46m/s2£»
¢ÚÒªÑé֤ţ¶ÙµÚ¶þ¶¨ÂÉ£¬ÐèÒªÓÃÌìƽ²â³öС³µµÄÖÊÁ¿£®
¢ÛA¡¢ÔÚʵÑéµÄ¹ý³ÌÖУ¬ÎÒÃÇÈÏΪÉþ×ÓµÄÀ­Á¦FµÈÓÚ¹³ÂëµÄÖØÁ¦mg£¬¶øÔÚС³µÔ˶¯Öл¹»áÊܵ½×èÁ¦£¬ËùÒÔÎÒÃÇÊ×ÏÈÐèҪƽºâĦ²ÁÁ¦£®¾ßÌåµÄ·½·¨ÊÇÊʵ±µæ¸ß³¤Ä¾°åÎÞ»¬ÂÖµÄÒ»¶Ë£¬Ê¹Î´¹Ò¹³ÂëµÄС³µÇ¡ÄÜÍÏ×ÅÖ½´øÔÈËÙÏ»¬£¬¹ÊAÕýÈ·£®
B¡¢¸ù¾ÝʵÑéÔ­Àí¿ÉÖª£¬ÔÚ¸ÃʵÑéÖÐÒÔ¼°Óô«¸ÐÆ÷Ö±½Ó²â³öÁËС³µËùÊÜÀ­Á¦´óС£¬Òò´Ë¶ÔС³µÖÊÁ¿ºÍËù¹Ò¹³ÂëÖÊÁ¿Ã»ÓоßÌåÒªÇ󣬹ÊBC´íÎó£®
D¡¢Êʵ±Ôö´ó¹³ÂëµÄÖÊÁ¿¿ÉÒÔ¼õСĦ²Á×èÁ¦²úÉúµÄÏà¶ÔÎó²î£¬¹ÊDÕýÈ·£®¹ÊÑ¡AD£®
£¨2£©¢Ù¡°Ë®¹ûµç³Ø¡±µÄÄÚ×èºÜ´ó£¬ÎªÁËʹµç±íÓÐÃ÷ÏÔʾÊý£¬Ó¦Ñ¡ÓÃ×èÖµ½Ï´óµÄ»¬¶¯±ä×èÆ÷£¬ÓÉÓÚ±ä×èÆ÷µÄµç×è½Ï´ó£¬Îª¼õСÎó²î£¬Ó¦Ñ¡Ôñͼ¼×Ëùʾµç·£¬£¨µçÁ÷±íÄÚ½Ó·¨£©£®
¾«Ó¢¼Ò½ÌÍø

¢ÚÓÉÌâÒâ¿ÉÖª£¬¡°Ë®¹ûµç³Ø¡±µÄÄÚ×èºÜ´ó£¬ÈôÑ¡ÓÃ0¡«20¦¸µÄ±ä×èÆ÷£¬µ±»¬¶¯´¥Í·Òƶ¯Ê±£¬µç±íµÄ¶ÁÊý¼¸ºõ²»±ä£¬ÎÞ·¨¶à´Î²âÁ¿£¬Ê¹ÊµÑéµÄÎó²î½Ï´ó£»ÎªÁ˼õСʵÑéÎó²î£¬Ó¦Ñ¡ÓÃ×èÖµ½Ï´óµÄ»¬¶¯±ä×èÆ÷B£®ÔڱպϿª¹ØÇ°£¬Ó¦°Ñ»¬¶¯±ä×èÆ÷µÄ×èÖµµ÷µ½×î´ó£®
¢ÛÁ¬½Ó×ø±êϵÄÚ¸÷µã£¬×÷³öU-IͼÏó£¬ÈçͼËùʾ£»ÓÉͼ¿ÉÖª£¬Í¼Ïß×ÝÖáµÄ½Ø¾à¼´Îªµç¶¯ÊÆ£¬ÔòE=1.5V£®Í¼ÏßµÄбÂÊ´óСµÈÓÚµçÔ´µÄÄÚ×裬
Ôòr=
¡÷U
¡÷I
=
1.5
3¡Á10-3
¦¸=500¦¸£®
¢ÜÓÉÓÚµçÁ÷±íµÄ·Öѹ£¬Ê¹µÃ·¶Ëµçѹ´æÔÚÎó²î£¬¶øµçÁ÷ûÓÐÎó²î£¬ÔËÓÃ
¾«Ó¢¼Ò½ÌÍø
ͼÏó·¨·Ö±ðÔÚU-IͼÉÏÓɲâÁ¿Êý¾Ý×÷³öµÄͼÏß1ºÍÐÞÕýÎó²îºóÕæʵֵ×÷³öµÄͼÏß2£¬ÓÉͼ¿´³ö£¬µç¶¯ÊÆûÓÐϵͳÎó²î£¬¼´µç¶¯ÊÆÖµÓëÕæʵֵÏàµÈ£¬ÄÚ×èµÄ²âÁ¿ÖµÆ«´ó£®
¹Ê´ð°¸Îª£º£¨1£©¢Ù0.40£¬1.46£»¢ÚÌìƽ£¬Ð¡³µµÄÖÊÁ¿£»¢ÛAD£»
£¨2£©¢Ùͼ¼×£»¢ÚB£¬×î´ó£»¢Û2.50£¬500£»¢ÜÏàµÈ£¬Æ«´ó£¬ÏµÍ³£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨1£©Ä³ÊÔÑéС×éÀûÓÃÀ­Á¦´«¸ÐÆ÷À´Ñé֤ţ¶ÙµÚ¶þ¶¨ÂÉ£¬ÊµÑé×°ÖÃÈçͼ£®ËûÃǽ«À­Á¦´«¸ÐÆ÷¹Ì¶¨ÔÚС³µÉÏ£¬Óò»¿ÉÉ쳤µÄϸÏß½«Æäͨ¹ýÒ»¸ö¶¨»¬ÂÖÓë¹³ÂëÏàÁ¬£¬ÓÃÀ­Á¦´«¸ÐÆ÷¼Ç¼С³µÊܵ½µÄÀ­Á¦FµÄ´óС£»Ð¡³µºóÃæ¹Ì¶¨Ò»´òµã¼ÆʱÆ÷£¬Í¨¹ýË©ÔÚС³µÉϵÄÖ½´ø£¬¿É²âÁ¿Ð¡³µÔȼÓËÙÔ˶¯µÄËÙ¶ÈÓë¼ÓËٶȣ®
¢ÙÈô½»Á÷µçµÄƵÂÊΪ50Hz£¬Ôò¸ù¾ÝÏÂͼËù´òÖ½´øµÄ´òµã¼Ç¼£¬ABÁ½µãµÄʱ¼ä¼ä¸ôΪ
0.1
0.1
 s£¬Ð¡³µ´Ë´ÎÔ˶¯¾­BµãʱµÄËÙ¶ÈvB=
0.40
0.40
m/s£¬Ð¡³µµÄ¼ÓËÙ¶Èa=
1.46
1.46
m/s2£®£¨vB¡¢aµÄ½á¹û¾ù±£Áôµ½Ð¡ÊýµãºóÁ½Î»£©

¢ÚÒªÑé֤ţ¶ÙµÚ¶þ¶¨ÂÉ£¬³ýÁË;ÖÐÌá¼°µÄÆ÷²Ä¼°ÒѲâ³öµÄÎïÀíÁ¿Í⣬ʵÑéÖл¹ÒªÊ¹ÓÃ
Ììƽ
Ììƽ
£¨ÌîÒÇÆ÷Ãû³Æ£©À´²âÁ¿
С³µÖÊÁ¿
С³µÖÊÁ¿
£¨ÌîÎïÀíÁ¿Ãû³Æ£©£®
¢ÛÓÉÓÚС³µËùÊÜ×èÁ¦fµÄ´óСÄÑÒÔ²âÁ¿£¬ÎªÁ˾¡Á¿¼õСʵÑéµÄÎó²î£¬Ð辡¿ÉÄܽµµÍС³µËùÊÜ×èÁ¦fµÄÓ°Ï죬ÒÔϲÉÈ¡µÄ´ëÂÃÖбØÒªµÄÊÇ£¨Ë«Ñ¡£©£º
AC
AC
£®
A£®Êʵ±µæ¸ß³¤Ä¾°åÎÞ»¬ÂÖµÄÒ»¶Ë£¬Ê¹Î´¹Ò¹³ÂëµÄС³µ±»ÇáÍƺóÇ¡ÄÜÍÏ×ÅÖ½´øÔÈËÙÏ»¬
B£®Ó¦Ê¹¹³Âë×ÜÖÊÁ¿mԶСÓÚС³µ£¨¼ÓÉÏ´«¸ÐÆ÷£©µÄ×ÜÖÊÁ¿M
C£®Ó¦Í¨¹ýµ÷½Ú¶¨»¬Âֵĸ߶ÈÈ·±£À­Ð¡³µµÄϸÉþÓëľ°åƽÐÐ
D£®¹³ÂëµÄ×ÜÖÊÁ¿mӦСЩ
£¨2£©Èçͼ1ËùʾΪijͬѧ¡°Ì½¾¿µ¯»Éµ¯Á¦¸úÉ쳤µÄ¹Øϵ¡±µÄʵÑé×°ÖÃͼ£¬ËùÓù³ÂëµÄÖØÁ¦Ï൱ÓÚ¶Ôµ¯»ÉÌṩÁËÏòÓҵĺ㶨µÄÀ­Á¦£®
£¨I£©ÊµÑéµÄ²½ÖèÈçÏ£º
¢Ù°ÑϸÉþºÍµ¯»ÉµÄС»·½áºÃ£¬ÈÃϸÉþ¿ç¹ý¶¨»¬ÂÖ£¬²¢½áºÃϸÉþÌ×£®
¢Ú´Ó¿Ì¶È³ßÉ϶Á³öµ¯»É×ó²à½áµãµ½Ð¡»·½áµãµÄ¾àÀ루¼´Ô­³¤£©£®
¢ÛÔÚϸÉþÌ×ÉϹÒÉÏ1¸öÒÑÖªÖÊÁ¿µÄ¹³Â룬´ýµ¯»ÉÉ쳤µ½Îȶ¨Ê±£¬
´Ó¿Ì¶È³ßÉ϶Á³öµ¯»ÉµÄ³¤¶È
´Ó¿Ì¶È³ßÉ϶Á³öµ¯»ÉµÄ³¤¶È
£¬ÔÙ¼ÆËã´ËʱµÄÉ쳤Á¿£¬ºÍ¹³ÂëµÄÖÊÁ¿Ò»²¢ÌîÈëÁÐ±í£®
¢Ü»»ÉÏ2¸ö¡¢3¸ö¡¢4¸ö¡¢5¸ö¹³Âë¹ÒÉÏϸÉþÌ×£»Öظ´¢ÛµÄ²½Ö裬µÃµ½Îå×éÊý¾Ý£®
¢ÝÒÔµ¯Á¦£¨¹³ÂëÖÊÁ¿»»Ëã¹ýÀ´£©Îª×Ý×ø±ê£¬ÒÔµ¯»ÉÉ쳤Á¿Îªºá×ø
±ê£¬¸ù¾ÝËù²âÊý¾ÝÔÚ×ø±êÖ½ÉÏÃèµã£¬×÷³öÒ»Ìõƽ»¬µÄÖ±Ïߣ¬
¹éÄɳöʵÑéµÄ½áÂÛ£®
£¨¢ò£©Èçͼ2Êǵ¯»Éµ¯Á¦FÓ뵯»ÉÉ쳤Á¿xµÄF-xͼÏߣ¬Óɴ˿ɵ¯µÃµ½½áÂÛ£º
µ¯Á¦FÓ뵯»ÉÉ쳤Á¿xΪÏßÐÔ¹Øϵ
µ¯Á¦FÓ뵯»ÉÉ쳤Á¿xΪÏßÐÔ¹Øϵ

ͼÏß²»¹ýÔ­µãµÄÔ­ÒòÊÇÓÉÓÚ
µ¯»ÉÓë×ÀÃæ¼°Éþ×ÓÓ뻬ÂÖ¼ä´æÔÚµÄĦ²ÁÔì³ÉµÄ
µ¯»ÉÓë×ÀÃæ¼°Éþ×ÓÓ뻬ÂÖ¼ä´æÔÚµÄĦ²ÁÔì³ÉµÄ
£®
£¨1£©Ä³ÊÔÑéС×éÀûÓÃÀ­Á¦´«¸ÐÆ÷ºÍ´òµã¼ÆʱÆ÷Ñé֤ţ¶ÙÔ˶¯¶¨ÂÉ£¬ÊµÑé×°ÖÃÈçͼ1£®ËûÃǽ«À­Á¦´«¸ÐÆ÷¹Ì¶¨ÔÚС³µÉÏ£¬Óò»¿ÉÉ쳤µÄϸÏß½«Æäͨ¹ýÒ»¸ö»¬ÂÖÓë¹³ÂëÏàÁ¬£¬ÓÃÀ­Á¦´«¸ÐÆ÷¼Ç¼С³µÊܵ½À­Á¦FµÄ´óС£»Ð¡³µºóÃæ¹Ì¶¨Ò»´òµã¼ÆʱÆ÷£¬Í¨¹ýË©ÔÚС³µÉϵÄÖ½´ø£¬¿É²âÁ¿Ð¡³µÔȼÓËÙÔ˶¯µÄËÙ¶ÈÓë¼ÓËٶȣ®Èô½»Á÷µçµÄƵÂÊΪ
10Hz£¬Ôò¸ù¾Ýͼ2Ëù´òÖ½´ø¼Ç¼£¬Ð¡³µ´Ë´ÎÔ˶¯¾­BµãʱµÄËÙ¶ÈvB=
 
m/s£¬
С³µµÄ¼ÓËÙ¶Èa=
 
m/s2£®
£¨2£©ÏÖÒª²âÁ¿Ä³Ð¡Á¿³ÌµçÁ÷±íµÄÄÚ×裬ÆäÄÚ×èÔÚ5¦¸¡«8¦¸Ö®¼ä£¬¿ÉÑ¡ÓõÄÆ÷²ÄÈçÏ£º
A£®´ý²âµçÁ÷±íA£¨Á¿³Ì10mA£©£»
B£®µçѹ±íV1£¨Á¿³Ì0.3V£¬ÄÚ×èÔ¼500¦¸£©
C£®µçѹ±íV2£¨Á¿³Ì3V£¬ÄÚ×èÔ¼3k¦¸£©£»
D£®»¬¶¯±ä×èÆ÷R1£¨×î´óµç×è10¦¸£©
E£®»¬¶¯±ä×èÆ÷R2£¨×î´óµç×è5¦¸£© F£®¶¨Öµµç×èR3£¨×èÖµ20¦¸£©
G£®µçÔ´E£¨µç¶¯ÊÆ3V£©H£®¿ª¹ØS¼°µ¼Ïß¿à¸É
ÒªÇó²âÁ¿½á¹û¾¡¿ÉÄܾ«È·ÇÒµçÁ÷±í¡¢µçѹ±íµÄʾÊýÄÜ´ÓÁ㿪ʼµ÷½Ú£®
¢ÙÔÚÈçͼ3·½¿òÄÚ»­³öʵÑéµç·ͼ²¢±êÃ÷·ûºÅ£»
¢ÚµçÁ÷±íAÄÚ×èµÄ±í´ïʽΪ£ºRA=
 
£¬Ê½Öи÷·ûºÅµÄÎïÀíÒâÒåΪ
 
£®¾«Ó¢¼Ò½ÌÍø
¾«Ó¢¼Ò½ÌÍø£¨1£©Ä³ÊÔÑéС×éÀûÓÃÀ­Á¦´«¸ÐÆ÷À´Ñé֤ţ¶ÙµÚ¶þ¶¨ÂÉ£¬ÊµÑé×°ÖÃÈçͼ£®ËûÃǽ«À­Á¦´«¸ÐÆ÷¹Ì¶¨ÔÚС³µÉÏ£¬Óò»¿ÉÉ쳤µÄϸÏß½«Æäͨ¹ýÒ»¸ö¶¨»¬ÂÖÓë¹³ÂëÏàÁ¬£¬ÓÃÀ­Á¦´«¸ÐÆ÷¼Ç¼С³µÊܵ½µÄÀ­Á¦FµÄ´óС£»Ð¡³µºóÃæ¹Ì¶¨Ò»´òµã¼ÆʱÆ÷£¬Í¨¹ýË©ÔÚС³µÉϵÄÖ½´ø£¬¿É²âÁ¿Ð¡³µÔȼÓËÙÔ˶¯µÄËÙ¶ÈÓë¼ÓËٶȣ®
¢ÙÈô½»Á÷µçµÄƵÂÊΪ50Hz£¬Ôò¸ù¾ÝÏÂͼËù´òÖ½´øµÄ´òµã¼Ç¼£¬Ð¡³µ´Ë´ÎÔ˶¯¾­BµãʱµÄËÙ¶ÈvB
 
m/s£¬Ð¡³µµÄ¼ÓËÙ¶Èa=
 
m/s2£®£¨vB¡¢aµÄ½á¹û¾ù±£Áôµ½Ð¡ÊýµãºóÁ½Î»£©¾«Ó¢¼Ò½ÌÍø
¢ÚÒªÑé֤ţ¶ÙµÚ¶þ¶¨ÂÉ£¬³ýÁËÇ°ÃæÌá¼°µÄÆ÷²Ä¼°ÒѲâ³öµÄÎïÀíÁ¿Í⣬ʵÑéÖл¹ÒªÊ¹ÓÃ
 
£¨ÌîÒÇÆ÷Ãû³Æ£©À´²âÁ¿³ö
 
£®£¨ÌîÎïÀíÁ¿Ãû³Æ£©£®
¢ÛÓÉÓÚС³µËùÊÜ×èÁ¦fµÄ´óСÄÑÒÔ²âÁ¿£¬ÎªÁ˾¡Á¿¼õСʵÑéµÄÎó²î£¬Ð辡¿ÉÄܽµµÍС³µËùÊÜ×èÁ¦fµÄÓ°Ï죬ÒÔϲÉÈ¡µÄ´ëÂÃÖбØÒªµÄÊÇ£¨Ë«Ñ¡£©£º
 
£®
A£®Êʵ±µæ¸ß³¤Ä¾°åÎÞ»¬ÂÖµÄÒ»¶Ë£¬Ê¹Î´¹Ò¹³ÂëµÄС³µ±»ÇáÍƺóÇ¡ÄÜÍÏ×ÅÖ½´øÔÈËÙÏ»¬
B£®Ó¦Ê¹¹³Âë×ÜÖÊÁ¿mԶСÓÚС³µ£¨¼ÓÉÏ´«¸ÐÆ÷£©µÄ×ÜÖÊÁ¿M
C£®¶¨»¬ÂÖµÄÂÖÖáÒª¾¡Á¿¹â»¬
D£®Êʵ±Ôö´ó¹³ÂëµÄ×ÜÖÊÁ¿m
£¨2£©Ä³ÐËȤС×éµÄͬѧÖÆ×÷ÁËÒ»¸ö¡°Ë®¹ûµç³Ø¡±£º½«-ͭƬºÍһпƬ·Ö±ð²åÈëһֻƻ¹ûÄÚ£¬¾Í¹¹³ÉÁËÒ»¸ö¼òµ¥µÄ¡°Ë®¹ûµç³Ø¡±£¬Æäµç¶¯ÊÆԼΪ1.5V£¬ÄÚ×èÔ¼Óм¸°ÙÅ·£®ÏÖÒªÇóÄãÓÃÁ¿³ÌºÏÊʵĵçѹ±í£¨ÄÚ×è½Ï´ó£©¡¢µçÁ÷±í£¨ÄÚ×è½ÏС£©À´²â¶¨Ë®¹ûµç³ØµÄµç¶¯ÊÆEºÍÄÚµç×èr£®
¢Ù±¾ÊµÑéµÄµç·Ӧ¸ÃÑ¡ÔñÏÂÃæµÄͼ¼×»òͼÒÒÖеģº
 

¾«Ó¢¼Ò½ÌÍø
¢ÚÈô¸ø³öµÄ»¬¶¯±ä×èÆ÷ÓÐÁ½ÖÖ¹æ¸ñ£ºA£¨0¡«20¦¸£©¡¢B£¨0¡«3k¦¸£©£®±¾ÊµÑéÖÐÓ¦¸ÃÑ¡ÓõĻ¬¶¯±ä×èÆ÷Ϊ£º
 
ͨµçÇ°Ó¦¸Ã°Ñ±ä×èÆ÷µÄ×èÖµµ÷ÖÁ
 
£®
¢ÛʵÑéÖвâ³öÁù×飨U£¬I£©µÄÖµ£¬ÔÚU-I×ø±êϵÖÐÃè³öͼ±ûËùʾµÄÁù¸öµã£¬·ÖÎöͼÖеĵ㼣¿ÉµÃ³öË®¹ûµç³ØµÄµç¶¯ÊÆΪE=
 
V£¬ÄÚµç×èΪr=
 
¦¸£®£¨¾ù±£Áô3λÓÐЧÊý×Ö£©
¢Ü¸ù¾ÝÄãÔÚ¢ÙÖÐËùÑ¡ÔñµÄµç·À´²âÁ¿µÃ³öµÄµç¶¯ÊÆEºÍÄÚµç×èrµÄ²âÁ¿ÖµÓëÕæʵֵÏà±È£ºµç¶¯ÊÆE
 
£¬ÄÚµç×èr
 
£®£¨¾ùÑ¡Ì¡°Æ«´ó¡±¡¢¡°ÏàµÈ¡±»ò¡°Æ«Ð¡¡±£©ÓÉ´ËÔì³ÉµÄʵÑéÎó²îÊôÓÚ
 
Îó²î£®£¨Ñ¡Ìϵͳ¡±»ò¡°Å¼È»¡±£©

£¨1£©Ä³ÊÔÑéС×éÀûÓÃÀ­Á¦´«¸ÐÆ÷À´Ñé֤ţ¶ÙµÚ¶þ¶¨ÂÉ£¬ÊµÑé×°ÖÃÈçͼ£®ËûÃǽ«À­Á¦´«¸ÐÆ÷¹Ì¶¨ÔÚС³µÉÏ£¬Óò»¿ÉÉ쳤µÄϸÏß½«Æäͨ¹ýÒ»¸ö¶¨»¬ÂÖÓë¹³ÂëÏàÁ¬£¬ÓÃÀ­Á¦´«¸ÐÆ÷¼Ç¼С³µÊܵ½µÄÀ­Á¦FµÄ´óС£»Ð¡³µºóÃæ¹Ì¶¨Ò»´òµã¼ÆʱÆ÷£¬Í¨¹ýË©ÔÚС³µÉϵÄÖ½´ø£¬¿É²âÁ¿Ð¡³µÔȼÓËÙÔ˶¯µÄËÙ¶ÈÓë¼ÓËٶȣ®
¢ÙÈô½»Á÷µçµÄƵÂÊΪ50Hz£¬Ôò¸ù¾ÝÏÂͼËù´òÖ½´øµÄ´òµã¼Ç¼£¬ABÁ½µãµÄʱ¼ä¼ä¸ôΪ______ s£¬Ð¡³µ´Ë´ÎÔ˶¯¾­BµãʱµÄËÙ¶ÈvB=______m/s£¬Ð¡³µµÄ¼ÓËÙ¶Èa=______m/s2£®£¨vB¡¢aµÄ½á¹û¾ù±£Áôµ½Ð¡ÊýµãºóÁ½Î»£©

¢ÚÒªÑé֤ţ¶ÙµÚ¶þ¶¨ÂÉ£¬³ýÁË;ÖÐÌá¼°µÄÆ÷²Ä¼°ÒѲâ³öµÄÎïÀíÁ¿Í⣬ʵÑéÖл¹ÒªÊ¹ÓÃ
______£¨ÌîÒÇÆ÷Ãû³Æ£©À´²âÁ¿______£¨ÌîÎïÀíÁ¿Ãû³Æ£©£®
¢ÛÓÉÓÚС³µËùÊÜ×èÁ¦fµÄ´óСÄÑÒÔ²âÁ¿£¬ÎªÁ˾¡Á¿¼õСʵÑéµÄÎó²î£¬Ð辡¿ÉÄܽµµÍС³µËùÊÜ×èÁ¦fµÄÓ°Ï죬ÒÔϲÉÈ¡µÄ´ëÂÃÖбØÒªµÄÊÇ£¨Ë«Ñ¡£©£º______£®
A£®Êʵ±µæ¸ß³¤Ä¾°åÎÞ»¬ÂÖµÄÒ»¶Ë£¬Ê¹Î´¹Ò¹³ÂëµÄС³µ±»ÇáÍƺóÇ¡ÄÜÍÏ×ÅÖ½´øÔÈËÙÏ»¬
B£®Ó¦Ê¹¹³Âë×ÜÖÊÁ¿mԶСÓÚС³µ£¨¼ÓÉÏ´«¸ÐÆ÷£©µÄ×ÜÖÊÁ¿M
C£®Ó¦Í¨¹ýµ÷½Ú¶¨»¬Âֵĸ߶ÈÈ·±£À­Ð¡³µµÄϸÉþÓëľ°åƽÐÐ
D£®¹³ÂëµÄ×ÜÖÊÁ¿mӦСЩ
£¨2£©Èçͼ1ËùʾΪijͬѧ¡°Ì½¾¿µ¯»Éµ¯Á¦¸úÉ쳤µÄ¹Øϵ¡±µÄʵÑé×°ÖÃͼ£¬ËùÓù³ÂëµÄÖØÁ¦Ï൱ÓÚ¶Ôµ¯»ÉÌṩÁËÏòÓҵĺ㶨µÄÀ­Á¦£®
£¨I£©ÊµÑéµÄ²½ÖèÈçÏ£º
¢Ù°ÑϸÉþºÍµ¯»ÉµÄС»·½áºÃ£¬ÈÃϸÉþ¿ç¹ý¶¨»¬ÂÖ£¬²¢½áºÃϸÉþÌ×£®
¢Ú´Ó¿Ì¶È³ßÉ϶Á³öµ¯»É×ó²à½áµãµ½Ð¡»·½áµãµÄ¾àÀ루¼´Ô­³¤£©£®
¢ÛÔÚϸÉþÌ×ÉϹÒÉÏ1¸öÒÑÖªÖÊÁ¿µÄ¹³Â룬´ýµ¯»ÉÉ쳤µ½Îȶ¨Ê±£¬______£¬ÔÙ¼ÆËã´ËʱµÄÉ쳤Á¿£¬ºÍ¹³ÂëµÄÖÊÁ¿Ò»²¢ÌîÈëÁÐ±í£®
¢Ü»»ÉÏ2¸ö¡¢3¸ö¡¢4¸ö¡¢5¸ö¹³Âë¹ÒÉÏϸÉþÌ×£»Öظ´¢ÛµÄ²½Ö裬µÃµ½Îå×éÊý¾Ý£®
¢ÝÒÔµ¯Á¦£¨¹³ÂëÖÊÁ¿»»Ëã¹ýÀ´£©Îª×Ý×ø±ê£¬ÒÔµ¯»ÉÉ쳤Á¿Îªºá×ø
±ê£¬¸ù¾ÝËù²âÊý¾ÝÔÚ×ø±êÖ½ÉÏÃèµã£¬×÷³öÒ»Ìõƽ»¬µÄÖ±Ïߣ¬
¹éÄɳöʵÑéµÄ½áÂÛ£®
£¨¢ò£©Èçͼ2Êǵ¯»Éµ¯Á¦FÓ뵯»ÉÉ쳤Á¿xµÄF-xͼÏߣ¬Óɴ˿ɵ¯µÃµ½½áÂÛ£º______
ͼÏß²»¹ýÔ­µãµÄÔ­ÒòÊÇÓÉÓÚ______£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø