ÌâÄ¿ÄÚÈÝ

¾«Ó¢¼Ò½ÌÍø»ØÐý¼ÓËÙÆ÷ÊǼÓËÙ´øµçÁ£×ÓµÄ×°Öã¬ÆäºËÐIJ¿·ÖÊÇ·Ö±ðÓë¸ßƵ½»Á÷µçÁ½¼«ÏàÁ¬½ÓµÄÁ½¸öDÐνðÊôºÐ£¬Á½ºÐ¼äµÄÏÁ·ìÖÐÐγɵÄÖÜÆÚÐԱ仯µÄÔÈÇ¿µç³¡£¬Ê¹Á£×ÓÔÚͨ¹ýÏÁ·ìʱ¶¼Äܵõ½¼ÓËÙ£®Á½DÐνðÊôºÐ´¦ÓÚ´¹Ö±Óںе×ÃæµÄÔÈÇ¿´Å³¡ÖУ¬ÈçͼËùʾ£¬ÉèÔÈÇ¿´Å³¡µÄ´Å¸ÐӦǿ¶ÈΪB£¬DÐνðÊôºÐµÄ°ë¾¶ÎªR£¬ÏÁ·ì¼äµÄ¾àÀëΪd£¬ÔÈÇ¿µç³¡¼äµÄ¼ÓËÙµçѹΪU£¬ÒªÔö´ó´øµçÁ£×Ó£¨µçºÉÁ¿ÎªqÖÊÁ¿Îªm£¬²»¼ÆÖØÁ¦£©Éä³öʱµÄ¶¯ÄÜ£¬ÔòÏÂÁз½·¨ÖÐÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A¡¢Ôö´óÔÈÇ¿µç³¡¼äµÄ¼ÓËÙµçѹB¡¢¼õСÏÁ·ì¼äµÄ¾àÀëC¡¢Ôö´ó´Å³¡µÄ´Å¸ÐӦǿ¶ÈD¡¢Ôö´óDÐνðÊôºÐµÄ°ë¾¶
·ÖÎö£º»ØÐý¼ÓËÙÆ÷ÀûÓõ糡¼ÓËٺʹų¡Æ«×ªÀ´¼ÓËÙÁ£×Ó£¬¸ù¾ÝÂåÂ××ÈÁ¦ÌṩÏòÐÄÁ¦Çó³öÁ£×ÓÉä³öʱµÄËٶȣ¬´Ó¶øµÃ³ö¶¯Äܵıí´ïʽ£¬¿´¶¯ÄÜÓëʲôÒòËØÓйأ®
½â´ð£º½â£ºÓÉqvB=m
v2
R
£¬½âµÃv=
qBR
m
£®
Ôò¶¯ÄÜEK=
1
2
mv2=
q2B2R2
2m
£¬Öª¶¯ÄÜÓë¼ÓËٵĵçѹÎ޹أ¬ÏÁ·ì¼äµÄ¾àÀëÎ޹أ¬Óë´Å¸ÐӦǿ¶È´óСºÍDÐκеİ뾶Óйأ¬Ôö´ó´Å¸ÐӦǿ¶ÈºÍDÐκеİ뾶£¬¿ÉÒÔÔö¼ÓÁ£×ӵĶ¯ÄÜ£®¹ÊC¡¢DÕýÈ·£¬A¡¢B ´íÎó£®
¹ÊÑ¡£ºCD£®
µãÆÀ£º½â¾ö±¾ÌâµÄ¹Ø¼üÖªµÀ»ØÐý¼ÓËÙÆ÷µç³¡ºÍ´Å³¡µÄ×÷Óã¬ÖªµÀÁ£×ÓµÄ×î´ó¶¯ÄÜÓë¼ÓËٵĵçѹÎ޹أ¬Óë´Å¸ÐӦǿ¶È´óСºÍDÐκеİ뾶Óйأ®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø