ÌâÄ¿ÄÚÈÝ
ijͬѧÓÃÈçͼËùʾµç·£¬²â»æ±êÓС°3.8 V,0.3 A¡±µÄСµÆÅݵĵÆË¿µç×èRËæµçѹU±ä»¯µÄͼÏó¡£
¢Ù³ýÁ˵¼ÏߺͿª¹ØÍ⣬ÓÐÒÔÏÂһЩÆ÷²Ä¿É¹©Ñ¡Ôñ:
µçÁ÷±í£ºA£± (Á¿³Ì100 mA,ÄÚ×èÔ¼2¦¸);
A£² (Á¿³Ì0.6 A,ÄÚ×èÔ¼0.3¦¸ );
µçѹ±í£ºV1 (Á¿³Ì5 V,ÄÚ×èÔ¼5 k¦¸ );
V2 (Á¿³Ì15 V,ÄÚ×èÔ¼15 k¦¸ );
µçÔ´£ºE1 (µç¶¯ÊÆΪ1.5 V£¬ÄÚ×èΪ0.2 ¦¸ );
E2 (µç¶¯ÊÆΪ4 V,ÄÚ×èԼΪ0.04¦¸ ).
»¬¶¯±ä×èÆ÷£ºR1 (×èÖµ·¶Î§0--10¦¸ )
R2 (×èÖµ·¶Î§0--2 k¦¸ )
ΪÁ˵÷½Ú·½±ã£¬²âÁ¿×¼È·£¬ÊµÑéÖÐӦѡÓÃ
µçÁ÷±í___________£¬µçѹ±í________£¬
»¬¶¯±ä×èÆ÷_________£¬µçÔ´________.(Ìî
Æ÷²ÄµÄ·ûºÅ)
¢Ú¸ù¾ÝʵÑéÊý¾Ý£¬¼ÆËã²¢Ãè»æ³öR-UµÄͼ
ÏñÈçͼËùʾ.ÓÉͼÏñ¿ÉÖª£¬´ËµÆÅÝÔÚ²»¹¤
×÷ʱ£¬µÆË¿µç×èΪ_________¦¸£»µ±Ëù¼Ó
µçѹΪ3.00 Vʱ£¬µÆË¿µç×èΪ______¦¸,£»
µÆÅÝʵ¼ÊÏûºÄµÄµç¹¦ÂÊΪ_________W¡£
¢Û¸ù¾ÝR-UͼÏñ£¬¿ÉÈ·¶¨Ð¡µÆÅݺĵ繦ÂÊPÓëÍâ¼ÓµçѹUµÄ¹Øϵ.·ûºÏ¸Ã¹ØϵµÄʾÒâͼÊÇÏÂÁÐͼÖÐ__
¢ÙA2 V1 R1 E2 ¢Ú1.5 11.5 0.78 ¢ÛA
½âÎö
A¡¢Í¼ÏóÈÎÒâʱ¿ÌµÄбÂÊ·´Ó³µÄÊǵçÈÝÆ÷µÄµçѹ | B¡¢Í¼ÏóÖÐÈÎÒâʱ¿ÌµÄµçÁ÷ÖµÓëµç×èRµÄ³Ë»ý¾ÍÊÇ´ËʱµçÈÝÆ÷µÄµçѹ | C¡¢Í¼Ïót=2sµ½t=4sͼÏóËùΧµÄÃæ»ý¾ÍÊǸöÎʱ¼äͨ¹ýµç×èRµÄµçÁ¿ | D¡¢Í¼ÏóËùΧµÄ×ÜÃæ»ýÓëµçÈÝÆ÷µçÈݵıÈÖµµÈÓÚµçÔ´µÄµç¶¯ÊÆ |