题目内容
(8分)图甲为测量物块与水平桌面之间动摩擦因数的实验装置示意图,细线平行于桌面,物块和遮光片的总质量为M、重物的质量为m,遮光片的宽度为d,两光电门之间的距离为s。让物块从光电门A的左侧由静止释放,分别测出遮光片通过光电门A、B所用的时间为tA和tB,用遮光片通过光电门的平均速度表示遮光片竖直中线通过光电门的瞬时速度。
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250020416662931.png)
⑴如果物块运动的加速度为a,则物块与水平桌面之间动摩擦因数μ为 ;
A.
B.![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825002041713930.png)
C.
D.![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825002041760734.png)
⑵利用实验中测出的物理量,算出物块运动的加速度a为 ;
A.
B.![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825002041791912.png)
C.
D.![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825002041822911.png)
⑶遮光片通过光电门的平均速度 (选填“大于”、“等于”或“小于”)遮光片竖直中线通过光电门的瞬时速度,由此会产生误差,请写出一种减小这一误差的方法。
答: 。
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250020416662931.png)
⑴如果物块运动的加速度为a,则物块与水平桌面之间动摩擦因数μ为 ;
A.
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825002041697949.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825002041713930.png)
C.
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825002041729807.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825002041760734.png)
⑵利用实验中测出的物理量,算出物块运动的加速度a为 ;
A.
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825002041775911.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825002041791912.png)
C.
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825002041807561.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825002041822911.png)
⑶遮光片通过光电门的平均速度 (选填“大于”、“等于”或“小于”)遮光片竖直中线通过光电门的瞬时速度,由此会产生误差,请写出一种减小这一误差的方法。
答: 。
⑴A;⑵B;⑶小于,减小遮光板的宽度。
试题分析:⑴对物块(含遮光片)、重物系统,根据牛顿第二定律有:mg-μMg=(M+m)a,解得;μ=
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825002041697949.png)
⑵物块(含遮光片)做匀加速直线运动,根据匀变速直线运动速度-位移关系有:2as=
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825002041869391.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825002041869403.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825002041885473.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825002041900481.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825002041791912.png)
⑶根据匀变速直线运动规律可知,对同一段运动而言,中点位移速度为:vs/2=
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825002041931695.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825002041947544.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
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