题目内容
如图为一列简谐横波沿x轴正方向传播,在t=0时刻波刚好传到P点,已知从此刻开始再经1.4s P点第二次出现波峰,则下列说法中正确的是
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241946148393183.jpg)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241946148393183.jpg)
A.这列波的波速是10m/s |
B.质点P在1s内所通过的路程是1m |
C.从图示情况开始,再经1s,质点Q第一次到达波峰 |
D.当波传到Q点以后,P、Q两质点的振动情况始终相同 |
BD
试题分析:从图中可得
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824194614995534.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824194615556514.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824194616430650.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824194617085516.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241946177401068.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824194618162458.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824194618754526.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824194615556514.png)
故选BD
点评:同相点是指相距波长的整数倍的质点,他们的振动情况完全一致,反相点指相距半波长整数倍的质点,他们的振动情况完全相反
![](http://thumb2018.1010pic.com/images/loading.gif)
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