ÌâÄ¿ÄÚÈÝ

ÈçͼËùʾ£¬°ë¾¶ R=1.6m µÄ¹â»¬Ô²»¡¹ìµÀλÓÚÊúֱƽÃæÄÚ£¬Ó볤 L=3m µÄ¾øԵˮƽ´«ËÍ´øƽ»¬Á¬½Ó£¬´«ËÍ´øÒÔ=3m/s µÄËÙ¶È˳ʱÕëת¶¯£¬´«ËÍ´øÓÒ²à¿Õ¼ä´æÔÚ»¥Ïà´¹ Ö±µÄÔÈÇ¿µç³¡ºÍÔÈÇ¿´Å³¡£¬µç³¡Ç¿¶È E=20N/C£¬´Å¸ÐӦǿ¶È B=3.0T£¬·½Ïò´¹Ö±Ö½ÃæÏòÍâ¡£Á½ ¸öÖÊÁ¿¾ùΪ µÄÎï¿é a ºÍ b£¬Îï¿é a ²»´øµç£¬b ´øµÄÕýµç²¢¾²Ö¹ÓÚÔ² »¡¹ìµÀ×îµÍµã£¬½« a Îï¿é´ÓÔ²»¡¹ìµÀ¶¥¶ËÓɾ²Ö¹ÊÍ·Å£¬Ô˶¯µ½×îµÍµãÓë b ·¢ÉúÕýÅö£¬Åöײʱ¼ä¼«¶Ì£¬ÅöºóÕ³ºÏÔÚÒ»Æð£¬À뿪´«ËÍ´øºóÒ»Æð·ÉÈ븴ºÏ³¡ ÖУ¬×îºóÒÔÓëˮƽ³É½ÇÂäÔÚµØÃæÉ쵀 P µã£¨Èçͼ£©£¬ ÒÑÖªÁ½Îï¿éÓë´«ËÍ´øÖ®¼äµÄ¶¯Ä¦²ÁÒòÊý¾ùΪ¦Ì=0.1£¬È¡ g=10£¬a¡¢b ¾ù¿É¿´×öÖʵ㡣Çó£º

£¨1£©Îï¿é a Ô˶¯µ½Ô²»¡¹ìµÀ×îµÍµãʱ¶Ô¹ìµÀµÄѹÁ¦£»

£¨2£©´«ËÍ´ø¾àÀëˮƽµØÃæµÄ¸ß¶È£»

£¨3£©Á½Îï¿éÅöײºóµ½ÂäµØǰ˲¼äµÄÔ˶¯¹ý³ÌÖУ¬a¡¢bϵͳ»úеÄܵı仯Á¿¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø