题目内容
如图所示的电路中,电路消耗的总功率P总=" 40" W,电阻R1 = 4Ω,R2 = 6Ω,电源内阻r = 0.6Ω,电源的效率η=94%,求:
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250013543813084.jpg)
(1)电源的输出功率P和电源的热功率P热;
(2)流过电源的电流I和路端电压U;
(3)ab两点间的电压Uba;
(4)电阻R3的值;
(5)电源的电动势E。
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250013543813084.jpg)
(1)电源的输出功率P和电源的热功率P热;
(2)流过电源的电流I和路端电压U;
(3)ab两点间的电压Uba;
(4)电阻R3的值;
(5)电源的电动势E。
(1)2.4W(2)2.0A 18.8V (3)4.8 V(4)7Ω(5)20V
试题分析:(1)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250013544121208.png)
而:
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825001354443869.png)
(2)由
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825001354459559.png)
解得
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825001354490497.png)
由
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825001354552452.png)
解得
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825001354568580.png)
(3)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250013545991097.png)
(4)因为
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825001354615776.png)
故
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825001354630740.png)
(5)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825001354661761.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
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