题目内容
如图,
,在c点固定一正电荷,将另一负电荷从a点移到b点,负电荷在a、b两点
的电势能分别为Epa、Epb,所受电场力分别为Fa、Fb,则
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250028331771067.jpg)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825002833161546.png)
的电势能分别为Epa、Epb,所受电场力分别为Fa、Fb,则
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250028331771067.jpg)
A.Epa>Epb | B.4Fa=Fb |
C.Epa<Epb | D.9Fa=Fb |
AD
试题分析:因C固定正电荷,把负电荷从a移到b点,电场力做正功,电势能减少,所以A对,C错;依题意有
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825002833193536.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825002833208734.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
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