题目内容
某高楼顶上吊下一根长绳,现给你一块秒表,一把只有几米长的米尺,一个带钩的重球,你能测出楼高吗?
楼高为
Δl
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003632613542.png)
(1)设绳长为l1,将重球挂在绳的下端点,让其摆动,测得周期T1(实际上需测得n次全振动所需时间t,T1=
).
(2)将重球挂在绳的另一位置,这时的摆长为l2,用米尺量出摆长的变化Δl,则Δl=l1-l2,让摆球摆动,测得此时的周期T2.(3)根据T=2π
可知,T1=2π
,T2=2π
,所以l1=
Δl,由此可测得绳长,即测得楼高为
Δl.
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003632628393.png)
(2)将重球挂在绳的另一位置,这时的摆长为l2,用米尺量出摆长的变化Δl,则Δl=l1-l2,让摆球摆动,测得此时的周期T2.(3)根据T=2π
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003632644475.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003632659500.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003632675671.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003632613542.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003632613542.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
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