题目内容
如图所示,质量为
的物体在恒力
的作用下,沿着竖直平整的墙壁向下做匀速直线运动,已知恒力
与竖直方向的夹角为
,试求物体与墙壁间的动摩擦因数
。![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241232007182071.jpg)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824123200593204.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824123200625200.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824123200625200.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824123200656200.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824123200671204.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241232007182071.jpg)
受力分析如图所示, (2分)
物体处于平衡状态,建立直角坐标,可得
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241232007493407.jpg)
(3分)
(3分)
又
(2分)
联立方程解得
(2分)
物体处于平衡状态,建立直角坐标,可得
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241232007493407.jpg)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824123200765581.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824123200781647.gif)
又
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824123200796411.gif)
联立方程解得
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824123200812720.gif)
略
![](http://thumb2018.1010pic.com/images/loading.gif)
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