题目内容
如图所示的电路中,灯泡A、B电阻相同,自感线圈L的直流电阻不能忽略。先接通电键S,使电路达到稳定后,再断开电键。下面关于流过A、B两灯的电流随时间变化的图像中正确的是
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250008565612781.png)
A.
B.![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250008565922228.png)
C.
D.![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250008566234850.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250008565612781.png)
A.
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250008565761909.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250008565922228.png)
C.
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250008566074811.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250008566234850.png)
BD
试题分析:在接通电键的瞬间,由于自感线圈的阻碍作用,使得灯泡A中的电流逐渐增强,并达到正常时的稳定值,选项B正确。正常工作以后,由于线圈有直流电阻,因此A灯所在支路电阻大,而电流弱,B灯电流强。在断电的瞬间,两灯泡自成回路,线圈发挥自感作用,给B反向供电,电流强度一下子突变为A灯泡原来的数值,并逐渐衰减为零,选项D正确。
![](http://thumb2018.1010pic.com/images/loading.gif)
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