ÌâÄ¿ÄÚÈÝ

18£®£¨¶àÑ¡£©¹ØÓÚÔȱäËÙÖ±ÏßÔ˶¯µÄλÒÆÓëʱ¼äµÄ¹Øϵ£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®Î»Òƹ«Ê½x=v0t+$\frac{1}{2}$at2Ö»ÊÊÓÃÓÚÔȱäËÙÖ±ÏßÔ˶¯
B£®Æ½¾ùËٶȹ«Ê½$\overline{v}$=$\frac{{v}_{0}+v}{2}$ÊÊÓÃÓÚÈκÎÖ±ÏßÔ˶¯
C£®×öÔȱäËÙÖ±ÏßÔ˶¯µÄÎïÌåµÄ³õËÙ¶ÈÔ½´ó£¬ÔÚʱ¼ätÄÚµÄλÒƾÍÔ½´ó
D£®v-tͼÏóÖÐͼÏóÓë×ø±êÖáΧ³ÉµÄÃæ»ý²»½ö¿ÉÒÔ±íʾλÒƵĴóС£¬Ò²¿É±íʾλÒƵķ½Ïò

·ÖÎö ÔȱäËÙÖ±ÏßÔ˶¯µÄλÒÆʱ¼ä¹Øϵ$x={v}_{0}t+\frac{1}{2}a{t}^{2}$£¬ÔȱäËÙÖ±ÏßÔ˶¯µÄƽ¾ùËٶȹ«Ê½$\overline{v}=\frac{v+{v}_{0}}{2}$£®

½â´ð ½â£ºA¡¢Î»Òƹ«Ê½$x={v}_{0}t+\frac{1}{2}a{t}^{2}$Ö»ÊÊÓÃÓÚÔȱäËÙÖ±ÏßÔ˶¯£¬¹ÊAÕýÈ·£»
B¡¢Æ½¾ùËٶȹ«Ê½$\overline{v}=\frac{v+{v}_{0}}{2}$½öÊÊÓÃÓÚÔȱäËÙÖ±ÏßÔ˶¯£¬¹ÊB´íÎó£»
C¡¢ÔȱäËÙÖ±ÏßÔ˶¯ÔÚtʱ¼äÄÚµÄλÒƳýÁ˸ú³õËÙ¶ÈÓйØÍ⻹Óë¼ÓËÙ¶ÈÓйأ¬¹ÊC´íÎó£»
D¡¢v-tͼÏóÖÐͼÏóÓë×ø±êÖáΧ³ÉµÄÃæ»ý²»½ö¿ÉÒÔ±íʾλÒƵĴóС£¬Ò²¿ÉÒÔ±íʾλÒƵķ½Ïò£¬¼´ÔÚʱ¼äÖáÉÏ·½µÄÃæ»ý±íʾÕýÏòλÒÆ£¬Ï·½µÄÃæ»ý±íʾ¸ºÏòλÒÆ£¬¹ÊDÕýÈ·£®
¹ÊÑ¡£ºAD£®

µãÆÀ ÕÆÎÕÔȱäËÙÖ±ÏßÔ˶¯µÄλÒÆʱ¼ä¹ØϵºÍƽ¾ùËٶȹ«Ê½ÊÇÕýÈ·½âÌâµÄ¹Ø¼ü£¬ÔÚ¼ÇÒ乫ʽµÄͬʱҪ¼Çס¹«Ê½ÊÊÓÃÌõ¼þ£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø