题目内容
某同学做了一次较为精确的测定匀加速直线运动的加速度的实验,实验所得到的纸带如图所示, 设0点是计数的起始点,相邻两计数点之间的时间间隔为0.1s。计数点0至2之间距离是9cm,0至3之间距离是15cm,则计数点1与0点的距离s1应为 cm,打计数点1时物体的速度大小是 m/s ;物体的加速度a = m/s2.![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408242008458643266.jpg)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408242008458643266.jpg)
(1) 4 (2) 0.45 (3) 1
试题分析:从图中可得:
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824200846160979.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824200847034515.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824200847626568.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824200848250607.png)
点评:本题难度较小,对于该实验,灵活应用匀变速直线运动规律是关键
![](http://thumb2018.1010pic.com/images/loading.gif)
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