ÌâÄ¿ÄÚÈÝ

£¨14·Ö£©Ò»ÖÊÁ¿Îªm=2kgµÄľ¿é·ÅÔÚˮƽµØÃæÉÏ£¬ÈçͼËùʾ¡£ÔÚÁ¦F×÷ÓÃÏ´Ӿ²Ö¹¿ªÊ¼ÔȼÓËÙÔ˶¯£¬¾­Ê±¼ät³·È¥Á¦F£¬Ä¾¿é×÷ÔȼõËÙÔ˶¯Ö±µ½Í£Ö¹¡£´Óľ¿é¿ªÊ¼Ô˶¯Æð¼Æʱ£¬Ï±í¸ø³öÁËijЩʱ¿Ìľ¿éµÄ˲ʱËٶȡ£

ʱ¿Ì£¨s£©
1.0
2.0
3.0
5.0
7.0
9.0
11.0
Ëٶȣ¨m/s£©
4.0
8.0
12.0
14.0
10.0
6.0
2.0.
¸ù¾Ý±íÖеÄÊý¾Ýͨ¹ý·ÖÎö¡¢¼ÆËãÏÂÁÐÎÊÌ⣺

£¨1£©Ä¾¿éÓëµØÃæ¼äµÄ¶¯Ä¦²ÁÒòÊý¦Ì
£¨2£©Á¦F´óС
£¨3£©Ä¾¿éͨ¹ýµÄ×Ü·³ÌÊǶàÉÙ£¿

£¨1£©0.2£¨2£©12N£¨3£©96m

½âÎöÊÔÌâ·ÖÎö£º£¨1£©ÓɱíÖÐÊý¾Ý¿ÉÖª£º¼õËÙʱ¼ÓËٶȴóСa2="2" m/s2£¨2·Ö£©
f="m" a2
½âµÃ¦Ì=0.2£¨2·Ö£©
£¨2£©ÓɱíÖÐÊý¾Ý¿ÉÖª¼ÓËÙʱ¼ÓËٶȴóСa1=4m/s2£¨2·Ö£©
F-f="m" a1
F=12N£¨2·Ö£©
£¨3£©·ÖÎöͼÖÐÊý¾Ý¿ÉÒÔÖªµÀ£¬×î´óËÙ¶ÈÓ¦¸Ã³öÏÖÔÚ3s-5sÖ®¼äijµã£¬Éè³öÏÖÔÚ3sºótʱ¿Ì£¬ÓÉÔ˶¯Ñ§¹«Ê½µÃ£¬½âµÃt=1s,ËùÒÔ´Ó¾²Ö¹µ½×î´óËٶȵÄʱ¼äΪ4s,×î´óËÙ¶ÈΪ
¼õËÙËùÓÃʱ¼äΪ£º£¬ËùÒÔÔ˶¯µÄ×Üʱ¼äΪ12s.
Ô˶¯µÄ×ÜλÒÆΪ£º
¿¼µã£º±¾Ì⿼²éÁËÔȱäËÙÖ±ÏßÔ˶¯µÄ¹æÂɼ°Ó¦ÓÃ

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø