ÌâÄ¿ÄÚÈÝ
ÓÃÌæ´ú·¨²âµçÁ÷±íÄÚµç×èµÄµç·ÈçͼËùʾ.Æ÷²Ä£º´ý²âµçÁ÷±íA(Á¿³Ì0¡ª10 mA£¬ÄÚ×èRAԼΪ30 ¦¸)£»µçÁ÷±íA¡ä(Á¿³Ì50 mA)£»µç×èÏäR1(0¡ª999.9 ¦¸)£¬»¬¶¯±ä×èÆ÷R2(0¡ª500 ¦¸)£»µçÔ´(E=3 V£¬rÔ¼1¡ª2 ¦¸).(1)»¬¶¯±ä×èÆ÷»¬Æ¬PÔÚʵÑ鿪ʼǰӦ·ÅÔÚ____________¶Ë.½«µ¥µ¶Ë«ÖÀ¿ª¹ØSÏȽӡ°
(2)½«¿ª¹ØS½Ó¡°
(3)Ôò´ý²â°²Åà±íAµÄÄÚµç×èRA=_______________________________;
(4)д³ö²âÁ¿ÔÀí(Ö¤Ã÷¹ý³Ì)__________________________________________________.
(1)b
(2)µçÁ÷±íA¡äʾÊýÈÔΪI¡ä£¬¶Á³ö´Ëʱµç×èÏäµÄ¶ÁÊýR1
(3)R1
(4)¿ª¹ØSÏȽӡ°
½âÎö£º£¨1£©Òòµç¼ü½ÓͨºóӦʹµç·ÖеĵçÁ÷±È½ÏС£¬ËùÒÔ»¬¶¯±ä×èÆ÷»¬Æ¬PÓ¦ÖÃÓÚb¶Ë.
(2)ÓÉÌæ´ú·¨µÄÔÀí¿ÉÖª£ºµ±¸ÄÓõç×èÏäR1ºó£¬¶øµç·ÆäËûÌõ¼þ²»±äʱ£¬Èôµç·ÖеĵçÁ÷ÈÔΪI¡ä,Ôò¿ÉÒÔÈÏΪRA=R1.
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿