ÌâÄ¿ÄÚÈÝ

Èçͼ6-5-6ËùʾÊÇÉú²úÁ÷Ë®ÏßÉϵÄƤ´ø´«Êä×°Ö㬴«Êä´øÉϵȼä¾àµØ·Åןܶà°ë³ÉÆ·²úÆ·.AÂÖ´¦×°Óйâµç¼ÆÊýÆ÷£¬Ëü¿ÉÒԼǼͨ¹ýA´¦µÄ²úÆ·ÊýÄ¿.ÒÑÖª²âµÃÂÖA¡¢BµÄ°ë¾¶·Ö±ðΪrA=20 cm,rB=10 cm£¬ÏàÁÚÁ½²úÆ·¾àÀëΪ30 cm£¬1 minÄÚÓÐ41¸ö²úƷͨ¹ýA´¦.Çó£º

ͼ6-5-6

(1)²úÆ·Ëæ´«Êä´øÒƶ¯µÄËٶȴóС£»

(2)A¡¢BÂÖÔµÉϵÄÁ½µãP¡¢Q¼°AÂְ뾶ÖеãMµÄÏßËٶȺͽÇËٶȴóС£¬²¢ÔÚͼÖл­³öÏßËٶȷ½Ïò£»

(3)Èç¹ûAÂÖÊÇͨ¹ýĦ²Á´ø¶¯CÂÖת¶¯£¬ÇÒrC=5 cm£¬ÔÚͼÖÐÃè³öCÂÖµÄת¶¯·½Ïò£¬Çó³öCÂֵĽÇËÙ¶È(¼ÙÉèÂÖ²»´ò»¬).

½âÎö£ºÊ×ÏÈÃ÷È·²úÆ·Óë´«ËÍ´ø±£³ÖÏà¶Ô¾²Ö¹µÄÌõ¼þÏ£¬²úÆ·ËٶȵĴóС¾ÍµÈÓÚ´«ËÍ´øÉÏÿһµãËٶȵĴóС£¬ÔÚ´«ËÍ´ø²»´ò»¬µÄÌõ¼þÏ£¬´«ËÍ´øÉϸ÷µãÔ˶¯ËٶȵĴóС¶¼µÈÓÚA¡¢BÂÖÔµÉϵãµÄÏßËٶȵĴóС.ÓÉ´«ËÍ´øÏàÁÚ²úÆ·µÄ¼ä¾à¼°µ¥Î»Ê±¼äÄÚͨ¹ýA´¦µÄ²úÆ·µÄ¸öÊý¿ÉÒÔÈ·¶¨³öƤ´øÉϵãµÄËٶȣ¬½ø¶øÖªµÀA¡¢BÂÖÔµÉϵÄÁ½µãP¡¢QÏßËٶȵĴóС.È»ºóÓÉÏßËÙ¶ÈÓë½ÇËٶȵĹØϵ£¬Çó³öA¡¢BÁ½ÂֵĽÇËٶȼ°AÂְ뾶ÖеãMµÄÏßËٶȼ°CÂֵĽÇËÙ¶È.

ÓÉÌâÒâÖª£¬1·ÖÖÓÄÚÓÐ41¸ö²úƷͨ¹ýA´¦£¬ËµÃ÷1·ÖÖÓÄÚ´«Êä´øÉÏÿµãÔ˶¯µÄ·³ÌΪÁ½²úÆ·¼ä¾àµÄ40±¶.Éè´«Êä´øÔ˶¯ËٶȴóСΪv£¬Ôò(1)v= m/s=0.2 m/s.

(2)vP=vQ=0.2 m/s£¬AÂְ뾶ÉϵÄMµãÓëPµãµÄ½ÇËÙ¶ÈÏàµÈ£¬¹Ê

vM=¡Á0.2 m/s=0.1 m/s

¦ØP=¦ØM= rad/s=1 rad/s,¦ØQ=2¦ØP=2 rad/s.

(3)CÂÖµÄת¶¯·½ÏòÈçͼËùʾ£¬Èç¹ûÁ½Âּ䲻´ò»¬£¬ÔòËüÃǵĽӴ¥´¦ÊÇÏà¶Ô¾²Ö¹µÄ£¬¼´ËüÃÇÂÖÔµµÄÏßËٶȴóСÊÇÏàµÈµÄ£¬ËùÒÔ¦ØCrC=¦ØArA.

CÂֵĽÇËٶȦØC=  ¦ØA=¡Á1 rad/s=4 rad/s.

´ð°¸£º(1)0.2 m/s  (2)vP=vQ=0.2 m/s     vM=0.1 m/s     ¦ØP=¦ØM=1 rad/s      ¦ØQ=2 rad/s  (3)¦ØC=4 rad/s


Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø