题目内容
如图甲所示为一简谐波在t=0时刻的图象,图乙所示为x=4m处的质点P的振动图象,则下列判断正确的是 ( )
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241329433633006.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241329433633006.png)
A.这列波的波速是2m/s |
B.这列波的传播方向沿x正方向 |
C.t=3.5s时P点的位移为0.2m |
D.从t=0时刻开始P点的振动方程为![]() |
ACD
(1)由图象可知波长
=4m,周期T=2s,波速
2m/s,A项正确;t=0时刻P点向-y方向振动,则波向x负方向传播,B项错;t=3.5s
T,此时P点位于波峰位置,C项正确;由图乙知
,初相位为
,振动方程为
m,D项正确
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824132943425323.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824132943456540.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824132943488438.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824132943519667.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824132943550309.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824132943394849.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
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