题目内容
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241201586033531.jpg)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241201586192949.jpg)
(1)1×103 (N/m) (2)2.5N
(1)平衡时有f弹=mg=2N
由胡克定律f=kx得
k=
=
=1×103 (N/m)
(2)当书匀速运动时有f弹=f滑
而弹力f弹=KX/ =1×103 ×2.5×103 =2.5(N)
即书与桌面间的摩擦力f滑=2.5N
由胡克定律f=kx得
k=
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824120158634232.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824120158650338.gif)
(2)当书匀速运动时有f弹=f滑
而弹力f弹=KX/ =1×103 ×2.5×103 =2.5(N)
即书与桌面间的摩擦力f滑=2.5N
![](http://thumb2018.1010pic.com/images/loading.gif)
练习册系列答案
相关题目