ÌâÄ¿ÄÚÈÝ

ÈçͼËùʾ£¬ÔÚÕæ¿ÕÖеÄÊúֱƽÃæÄÚ£¬Óó¤Îª2LµÄ¾øÔµÇá¸ËÁ¬½ÓÁ½¸öÖÊÁ¿¾ùΪmµÄ´øµçСÇòAºÍB£¬AÇòµÄµçºÉÁ¿Îª+4q£¬BÇòµÄµçºÉÁ¿Îª¡ª3q£¬×é³ÉÒ»´øµçϵͳ¡£ÐéÏßMNÓëPQƽÐÐÇÒÏà¾à3L£¬¿ªÊ¼Ê±PQǡΪ¸ËµÄÖд¹Ïß¡£ÔÚMNÓëPQ¼ä¼ÓÊúÖ±ÏòÉϵÄÔÈÇ¿µç³¡£¬Ç¡ÄÜʹ´øµçϵͳ¾²Ö¹²»¶¯¡£ÏÖʹµç³¡Ç¿¶ÈͻȻ¼Ó±¶£¨ÒÑÖªµ±µØÖØÁ¦¼ÓËÙ¶ÈΪg£©£¬Çó£º
£¨1£©BÇò¸Õ½øÈëµç³¡Ê±µÄËÙ¶Èv1µÄ´óС£»
£¨2£©BÇòµÄ×î´óλÒƼ°´Ó¿ªÊ¼¾²Ö¹µ½×î´óλÒÆ´¦BÇòµçÊÆÄܵı仯Á¿£»
£¨3£©´øµçϵͳÔ˶¯µÄÖÜÆÚT¡£
£¨1£©Éè´øµçϵͳ¾²Ö¹Ê±µç³¡Ç¿¶ÈΪE£¬ÓÐ2mg =4qE£¬½âµÃ     ¢Ù
µç³¡Ç¿¶È¼Ó±¶ºó£¬´Ó¿ªÊ¼¾²Ö¹µ½B½øÈëµç³¡£¬¸ù¾Ý¶¯Äܶ¨ÀíÓÐ
            ¢Ú
ÁªÁ¢¢Ù¢ÚµÃBÇò¸Õ½øÈëµç³¡Ê±µÄËÙ¶È
£¨2£©ÉèBÇòÔڵ糡ÖеÄ×î´óλÒÆΪs£¬¾­·ÖÎöÖªAÇòÏòÉÏÔ½¹ýÁËMN£¬¸ù¾Ý¶¯Äܶ¨ÀíÓÐ

½âµÃs=1.2L  ¹ÊBÇòµÄ×î´óλÒÆs×Ü=2.2L
µç³¡Á¦¶ÔBÇò×ö¹¦
ÔòBÇòµçÊÆÄÜÔö¼Ó3.6mgL
£¨3£©´øµçϵͳÏòÉÏÔ˶¯·ÖΪÈý½×¶Î£¬µÚÒ»½×¶ÎÔȼÓËÙÔ˶¯£¬¾ÝÅ£¶ÙµÚ¶þ¶¨ÂÉÓÐ
£¬Ô˶¯Ê±¼ä£»
µÚ¶þ½×¶ÎÔȼõËÙÔ˶¯£¬Í¬Àí¿ÉµÃ
ÉèAÇò³öµç³¡Ê±ËÙ¶ÈΪv2£¬¸ù¾ÝÔ˶¯Ñ§¹«Ê½ÓУº£¬½âµÃ£¬£»
µÚÈý½×¶ÎÔȼõËÙÔ˶¯£¬£¬
ÔòÔ˶¯ÖÜÆÚ
ÂÔ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø