题目内容
有一薄壁玻璃瓶,在温度恒定情况下,称量质量三次:(1)瓶抽空了;(2)瓶内装有一个大气压的空气;(3)瓶内装满1.5个大气压的未知气体.三次称量的数值是:
.试计算未知气体的相对分子质量.已知空气的相对分子质量为29.瓶壁的体积与瓶内的容积相比可以忽略不计.
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241201162651310.gif)
43.5
设容器的体积为V,并设将未知气体转化成一个大气压时的体积为
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824120116296948.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824120116311952.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241201163271016.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241201163431013.gif)
对于未知气体有:1.5
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241201163581070.gif)
则未知气体在一个大气压下且体积为V时所具有的质量为:
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241201163741137.gif)
所以该气体的相对分子量为:
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241201163891236.gif)
![](http://thumb2018.1010pic.com/images/loading.gif)
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