题目内容
通过两定值电阻R1、R2的电流I和其两端电压U的关系图象分别如图所示,由图可知两电阻的阻值之比
等于 ( )
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241449232422080.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824144923196443.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241449232422080.png)
A.![]() | B.![]() |
C.![]() | D.![]() |
:A
:
试题分析:根据部分电路欧姆定律可知
,图中图线的斜率的倒数即为电阻,所以
,A对
故选A
点评:伏安特性曲线若是通过原点的直线,那么其斜率的倒数等于导体的电阻值,而且欧姆定律
对这段导体也是适用的.
试题分析:根据部分电路欧姆定律可知
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824144923617516.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241449237881188.png)
故选A
点评:伏安特性曲线若是通过原点的直线,那么其斜率的倒数等于导体的电阻值,而且欧姆定律
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824144923835510.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
练习册系列答案
相关题目