题目内容
如图所示,实线为电场线,虚线为带电粒子(不计重力)的运动轨迹,电场中A、B两点的电势分别为φA、φB,粒子在A、B两点的速度大小分别为vA、vB,加速度大小分别为aA、aB,电势能分别为EpA、EpB,则下列关系中正确的是( )
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241506348571454.jpg)
A.φA>φB B.vA>vB
C.aA>aB D.EpA>EpB
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241506348571454.jpg)
A.φA>φB B.vA>vB
C.aA>aB D.EpA>EpB
CD
试题分析:沿电场线方向电势减小,所以
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824150634981514.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824150635106473.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824150635262609.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824150635106473.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824150635262609.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824150635527490.png)
点评:若粒子仅在电场力作用下,在电场中偏转,受到的电场力方向指向轨迹的凹侧,
![](http://thumb2018.1010pic.com/images/loading.gif)
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