题目内容
如图所示,实线是一列简谐横波在t1时刻的波形图,虚线是在t2=(t1+0.2)s时刻的波形图.若波速为35m/s,则质点M在t1时刻的振动方向为 ;若在t1到t2的时间内,M通过的路程为1m,则波速为 m/s.![](http://thumb.1010pic.com/pic2/upload/papers/20140824/2014082416585654911282.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/2014082416585654911282.png)
向下 25
试题分析:根据图像可知,图为波动图象,根据图像可知,波长为4m。若机械波向右传播,则0.2s相当于0.25个周期或者通式为:
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824165856845779.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824165857329707.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824165857672824.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824165858374807.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824165858858747.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824165859294843.png)
点评:本题考查了机械波的传播特点。本体十分具有代表性,通过分析波形,找出波传播的通式。利用质点振动找出振动周期从而求解。
![](http://thumb2018.1010pic.com/images/loading.gif)
练习册系列答案
相关题目