题目内容
(1)有一群氢原子处在量子数n=3的激发态,画一能级图,在图上用箭头标明这些氢原子能发出几种光谱线.
(2)计算这几条光谱线中最短的波长.(已知En =E1/n2,普朗克常量为6.63×10-34J.s )
(1)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241200136623544.jpg)
(2) 165 nm.
(1)氢原子一共发出3种光谱线,如右图所示:
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241200136623544.jpg)
(2)从n=3的激发态跃迁到基态时,放出的光子能量最大,波长最短.
由E3-E1=
得:
λ=
=
m
=1.65×10-7 m="165" nm.
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241200136623544.jpg)
(2)从n=3的激发态跃迁到基态时,放出的光子能量最大,波长最短.
由E3-E1=
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824120013693369.gif)
λ=
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824120013849457.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241200138651041.gif)
=1.65×10-7 m="165" nm.
![](http://thumb2018.1010pic.com/images/loading.gif)
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