题目内容
(6分)一列沿x轴传播的简谐横波,t=0时刻的波形如图所示,此时质点P恰在波峰,质点Q恰在平衡位置且向上振动。再过0.2s,质点Q第一次到达波峰,则下列说法正确的是
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408242226070153670.jpg)
E.0至0.9s时间内P点通过的路程为0.9 m
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408242226070153670.jpg)
A.波沿x轴负方向传播 |
B.波的传播速度为30m/s |
C.1s末质点P的位移为零 |
D.质点P的振动位移随时间变化的关系式为![]() |
BC(6分,少选得3分,有选错的得0分)
试题分析:由题意质点Q恰在平衡位置且向上振动,可知波沿x轴正方向传播,故选项A错误.由题,图示时刻再过0.2 s,质点Q第一次到达波峰,则周期T=0.8s,由图读出波长为λ="24" m,则波速为v=
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824222608278427.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824222608700504.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824222609152421.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
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