题目内容
某质点做匀减速直线运动,位移x与时间t的关系为x=10t-
(各物理量均采用国际单位制单位),则该物体运动的初速度为_____m/s,加速度为______
,3s内位移为_____m.(以初速度方向为正方向)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824130958853414.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824130958915507.png)
10 m/s -4 m/s2 12.5 m
由x=v0t+
=10t-
,知v0=10m/s,a=-4m/s2,
根据速度时间公式x=v0t+
得,3s内位移为12.5 m.
故本题答案为:10,-4,12.5.
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824130958962543.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824130958853414.png)
根据速度时间公式x=v0t+
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824130958962543.png)
故本题答案为:10,-4,12.5.
![](http://thumb2018.1010pic.com/images/loading.gif)
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