题目内容
如图所示,一截面为正三角形的棱镜,其折射率为√3,今有一束单色光从A8侧面入射,经AB面折射后,折射光线偏离入射光线300角。求光在AB面的入射角及AC面的折射角.![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241340567542411.jpg)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241340567542411.jpg)
入射角α=60°射角β=60°
(2)解析:由折射定律得n=
=
,
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/2014082413405695615594.png)
解得光在AB面的入射角α=60°。
由几何关系可知,θ=30°,
由折射定律n=![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824134056988592.png)
解得光在AC面的折射角β=60°.
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824134056800884.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824134056847337.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/2014082413405695615594.png)
解得光在AB面的入射角α=60°。
由几何关系可知,θ=30°,
由折射定律n=
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824134056988592.png)
解得光在AC面的折射角β=60°.
![](http://thumb2018.1010pic.com/images/loading.gif)
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