ÌâÄ¿ÄÚÈÝ

¾«Ó¢¼Ò½ÌÍø£¨1£©Ä³Í¬Ñ§Íê³É¡¶²â¶¨²£Á§µÄÕÛÉäÂÊ¡·ÊµÑéºó£¬¸ù¾Ý¿Î±¾Ë¼¿¼ÌâµÄË£Çó£¬ÓÖ¼ÌÐø¶Ô°ëÔ²ÖùÐβ£Á§×©ÕÛÉäÂʽøÐвⶨ£®ÈçͼËùʾΪʵÑé¹ý³ÌÖл­³öµÄ¹ýÔ²ÐÄ0µÄÈëÉä¹âP1P2µÄ¹â·ͼ£¬P3ÊǸÃÈëÉä¹â¾­²£Á§×©ÕÛÉäºóËù¾­¹ýµÄÒ»µã£®ÏÖ¸ÃͬѧÉí±ß½öÓеIJâÁ¿¹¤¾ßΪѧÉúÓÃÈý½Ç°å£®
¢ÙÇëÔÚͼÖÐ×÷³öÈëÉä¹â²£Á§×©ÕÛÉäºóµÄÕÛÉä¹âÏߣ»
¢Ú¸ù¾ÝÌṩµÄÆ÷²Ä£¬ÓÃÄã²âÁ¿³öÀ´µÄÁ¿±íʾ°ëÔ²ÖùÐβ£Á§×©ÕÛÉäÂʵıí´ïʽn=
 
£® £¨ÒªÇóËùÓÃÎïÀíÁ¿ÓëÄãÔÚͼÉϱêµÄ·ûºÅÏàÒ»Ö£©
£¨2£©Ð¡µÆÅݵÆË¿µÄµç×è»áËæζȵÄÉý¸ß¶ø±ä»¯£®ÎªÑо¿ÕâÒ»ÏÖÏó£¬Ä³Í¬Ñ§ÓÃKÁÐÆ÷²Äͨ¹ýʵÑé»æ³öÁËСµÆÅݵķü°²ÌØÐÔÇúÏßÈçÏÂͼËùʾ£®
³ýÁ˵çÔ´E¡¢Ð¡µÆÅÝL £¨¶î¶¨µçѹΪ2V£©¡¢µ¼ÏߺͿª¹ØÍ⣬»¹ÓÐÒÔÏÂһЩÆ÷²Ä¿É¹©Ñ¡Ôñ£º
µçÁ÷±í£ºA1£¨Á¿³Ì100mA£¬ÄÚ×èÔ¼2¦¸£©      A2£¨Á¿³Ì0.6A£¬ÄÚ×èÔ¼0.3¦¸£©
µçѹ±í£ºV1£¨Á¿³Ì3V£¬ÄÚ×èÔ¼5K¦¸£©         V2£¨Á¿³Ì15V£¬ÄÚ×èÔ¼15K¦¸£©
»¬¶¯±ä×èÆ÷£ºR1£¨×î´ó×èÖµ10¦¸£©R2£¨×î´ó×èÖµ2K¦¸£©
¢ÙΪÁ˵÷½Ú·½±ã£¬²âÁ¿×¼È·£¬ÊµÑéÖÐӦѡÓõçÁ÷±í
 
£¬µçѹ±í
 
»¬¶¯±ä×èÆ÷
 
£®£¨ÌîÆ÷²ÄµÄ·ûºÅ£©
¢ÚÔÚÏ¿òÖгö¸Ãͬѧ²ÉÓõÄʵÑéµç·ͼ£®
¾«Ó¢¼Ò½ÌÍø
¢Ûͨ¹ýʵÑ飬¸Ãͬѧ·¢ÏÖСµÆÅݵÆË¿µÄµç×è»áËæζȵÄÉý¸ß¶ø
 
£¨Ñ¡Ì¡°Ôö´ó¡±¡¢¡°¼õС¡±¡¢¡°²»±ä¡±£©£¬Ð¡µÆÅÝÕý³£¹¤×÷ʱµÄµç×èÊdz£ÎÂϵç×èµÄ
 
±¶£®
·ÖÎö£º£¨1£©¸ù¾ÝÕÛÉ䶨ÂÉ¿ÉÖª£¬´ÓÔ²ÐÄÉäÈëµÄ¹âÏߣ¬´Ó²£Á§×©Éä³öʱ£¬Ñذ뾶Éä³ö£¬¸ù¾Ý¹âÏßµÄÉä³öµã¿ÉÒÔÈ·¶¨³öÉä¹âÏߣ¬¸ù¾Ý¹â·ͼÕÒµ½ÈëÉä½ÇºÍÕÛÉä½Ç£¬¼´¿ÉÇó³ö¹âµÄÕÛÉäÂʱí´ïʽ£»
£¨2£©¸ù¾ÝСµÆÅݵķü°²ÌØÐÔÇúÏß¿ÉÖª£¬µçѹ×î´óֵΪ2V£¬µçÁ÷×î´óֵΪ0.5A£¬ÓÉ´Ë¿ÉÒÔÕýÈ·Ñ¡Ôñµçѹ±íºÍµçÁ÷±í£¬×¢ÒâÒªÇóÖ¸Õëƫת´óЩ£¬ÔÚÈý·ÖÖ®¶þ×óÓÒƫת×îºÃ£¬¸ÃʵÑé²ÉÓõÄÊÇ»¬¶¯±ä×èÆ÷µÄ·Öѹ½Ó·¨£¬Òò´Ë»¬¶¯±ä×èÆ÷Ñ¡Ôñ×èÖµ½ÏСµÄÄǸö£®
½â´ð£º¾«Ó¢¼Ò½ÌÍø½â£º£¨1£©¢Ù¸ù¾ÝP3λÖã¬È·¶¨Æä¹â·ͼÈçÏÂËùʾ£º
¢Ú¸ù¾ÝÕÛÉ䶨ÂÉÓУºn=
sini
sinr
=
d1
d2
£®
¹Ê´ð°¸Îª£º
d1
d2
£®
£¨2£©¢Ù¸ù¾ÝСµÆÅݵķü°²ÌØÐÔÇúÏß¿ÉÖª£¬µçѹ×î´óֵΪ2V£¬µçÁ÷×î´óֵΪ0.5A£¬ÔÚÑ¡µçѹ±íºÍµçÁ÷±íʱעÒâÒªÇóÖ¸Õëƫת´óЩ£¬ÔÚÈý·ÖÖ®¶þ×óÓÒƫת×îºÃ£¬Òò´Ëµçѹ±íÑ¡V1£¬µçÁ÷±íÑ¡A2£¬¸ÃʵÑé²ÉÓõÄÊÇ»¬¶¯±ä×èÆ÷µÄ·Öѹ½Ó·¨£¬Òò´Ë»¬¶¯±ä×èÆ÷Ñ¡Ôñ×èÖµ½ÏСµÄÄǸö£¬¹ÊÑ¡R1£®
¹Ê´ð°¸Îª£ºA2£¬V1£¬R1£®
¾«Ó¢¼Ò½ÌÍø¢ÚÓÉÌâÒâ¿ÉÖªµÆÅݵç×è½ÏС£¬Òò´Ë°²Åà±í²ÉÓÃÍâ½Ó·¨£¬¸ÃʵÑéµçѹÐèÒª´ÓÁãµ÷½Ú£¬¶øÇÒÐèÒª¶à²âÊý¾Ý£¬Òò´Ë»¬¶¯±ä×èÆ÷ÐèÒªÓ÷Öѹ½Ó·¨£¬¹ÊÔ­ÀíͼÈçÓÒͼËùʾ£º
¢Û¸ù¾ÝͼÏß¿ÉÖª£¬Ð¡µÆÅݵÆË¿µÄµç×è»áËæζȵÄÉý¸ß¶øÔö´ó£¬ÓÉͼÏß¿ÉÖª£¬µÆÅݵçѹΪ2Vʱ£¬µçÁ÷Ϊ0.5A£¬Òò´ËÕý³£¹¤×÷µç×èΪ£ºR=
U
R
=
2V
0.5A
=4¦¸
£»
¿ªÊ¼µçÁ÷ºÜÉÙʱµÄµç×èΪµÆÅݵij£Îµç×裬´óС´óԼΪ£ºR0=
U
I
=
0.2V
0.1A
=2¦¸
£¬
Òò´ËСµÆÅÝÕý³£¹¤×÷ʱµÄµç×èÊdz£ÎÂϵç×èµÄ£º
R
R0
=2±¶
£¬ÓÉÓÚÐèÒª¹À¶Á£¬Òò´ËÔÚ·¶Î§1.9¡«2.1ÄÚ¶¼ÕýÈ·£®
¹Ê´ð°¸Îª£º2£®
µãÆÀ£º¼¸ºÎ¹âѧÎÊÌ⣬ҪÃ÷È·¹â·ͼ£¬ÒÀ¾ÝÕÛÉ䶨ÂÉÇó½â£»ÒÇÆ÷Ñ¡Ôñ¡¢µç·Éè¼Æ¡¢Á¬½ÓʵÎïͼÊǵçѧʵÑé¾­³£¿¼²éµÄÖصã֪ʶ£¬¶ÔÓÚÕⲿ·Ö֪ʶÖ÷ÒªÔÚƽʱ¼ÓǿѵÁ·£¬¼ÓÉîÀí½â£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨1£©Ä³Í¬Ñ§ÓÃÂÝÐý²â΢Æ÷²âµÃij½ðÊôË¿µÄÖ±¾¶¦Õ£¬ÈçÏÂͼ1¼×Ëùʾ£®²âµÃijµ¥°ÚÍê³É40´ÎÈ«Õñ¶¯µÄʱ¼ät£¬ÈçÏÂͼ1ÒÒËùʾ£¬Ôò¦Õ=
2.735
2.735
mm£¬t=
78.3
78.3
s£®
£¨2£©ÈçͼËùʾµÄµç·£¬a¡¢b¡¢c¡¢dΪ½ÓÏßÖù£®µ±ºÏÉÏ¿ª¹ØKºó·¢ÏÖµÆL1ºÍL2¶¼²»ÁÁ£®¾­·ÖÎö£¬ÆäÔ­ÒòÖ»¿ÉÄÜÊǵÆL1»òL2µÄµÆË¿¶ÏÁË£®Ä³Í¬Ñ§½«ÍòÓñíµÄÑ¡Ôñ¿ª¹Ø´òµ½Ö±Á÷µçѹµ²²âa¡¢b¼äµÄµçѹʱÓжÁÊý£®¹Ê¿ÉÅж¨·¢Éú¶Ï·µÄÊǵÆ
L1
L1
£¨ÌîL1»òL2£©£®
²âÁ¿Ê±ÍòÓñíµÄºì±í±ÊÓ¦½Ó
a
a
£¨Ìîa»òb£©£®Èç¹ûËû½«ÍòÓñíµÄÑ¡Ôñ¿ª¹Ø´òµ½Å·Ä·µ²²¢¶Ì½Óµ÷Áãºó£¬Ö±½Ó²âL1µÄµç×裬Ôò²âÁ¿Ç°ËûÊ×ÏÈÓ¦×öµÄ¹¤×÷ÊÇ
¶Ï¿ª¿ª¹ØK
¶Ï¿ª¿ª¹ØK
£®
£¨3£©²â¶¨Ò»¸ö´ý²âµç×èRx£¨×èֵԼΪ200¦¸£©µÄ×èÖµ£¬³ýÁË´ý²âµç×èÍ⣬ʵÑéÊÒÌṩÁËÈçÏÂÆ÷²Ä£º
µç³Ø×éE£¨µç¶¯ÊÆΪ3V£¬ÄÚ×è²»¼Æ£©£»µçÁ÷±íA1£¨Á¿³ÌΪ0¡«10mA£¬ÄÚ×èr1ԼΪ50¦¸£©£»
µçÁ÷±íA2£¨Á¿³ÌΪ0¡«500¦ÌA£¬ÄÚ×èr2=1000¦¸£©£»»¬¶¯±ä×èÆ÷R1£¨×èÖµ·¶Î§Îª0¡«20¦¸£¬¶î¶¨µçÁ÷Ϊ2A£©£»
µç×èÏäR2£¨×èÖµ·¶Î§Îª0¡«9999¦¸£¬¶î¶¨µçÁ÷Ϊ1A£©£»¿ª¹ØS£¬µ¼ÏßÈô¸É£®
ÇëÔÚ´ðÌâÖ½Éϵķ½¿òÖл­³ö²âÁ¿Rx×èÖµµÄµç·ͼ£¬²¢ÔÚͼÖбêÃ÷¸÷Æ÷²ÄµÄ´úºÅ£®ÆäÖеç×èÏäµÄÈ¡ÖµÔÚ
5000
5000
¦¸×óÓÒ×îΪºÏÊÊ£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø