题目内容
如图所示,Ⅰ和Ⅱ是一对异名磁极,ab为放在其间的金属棒。ab和cd用导线连成一个闭合回路。当ab棒向左运动时,cd导线受到向下的磁场力。由此可知Ⅰ是____极,Ⅱ是____极,a、b、c、d四点的电势由高到低依次排列的顺序是 。 ![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241240463612777.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241240463612777.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124046392482.png)
cd导线受到向下的磁场力,根据左手定则可判断电流方向为由c到d,故有由b到a的电流,因为ab棒向左运动,根据右手定则,可知Ⅰ是S极,Ⅱ是N极,ab棒充当电源,a相当于电源正极,与c点电势相同,电流流过导体电势降低,d点通过导线到b端,所以势由高到低依次排列的顺序是![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124046408706.png)
故答案为:S N![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124046408706.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124046408706.png)
故答案为:S N
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124046408706.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
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