ÌâÄ¿ÄÚÈÝ
10£®Ä³Í¬Ñ§ÔÚ×ö¡¶ÓÃÓÍĤ·¨¹À²â·Ö×ӵĴóС¡·µÄʵÑéʱ°´ÏÂÁв½Öè½øÐУºA£®Óõιܽ«ÀÏʦÊÂÏÈÅäÖƺõľƾ«ÓÍËáÈÜÒº£¨´¿ÓÍËáÓëÈÜÒºÌå»ý±ÈΪ1£º500£©Ò»µÎÒ»µÎµØµÎÈëÁ¿Í²ÖУ¬½«260µÎ¸Ã¾Æ¾«ÓÍËáÈÜÒºµÎÈëÁ¿Í²Ê±£¬Á¿Í²¶ÁÊýΪ1mL£®
B£®ÓõιÜÔÚÈöÓÐðò×Ó·ÛµÄdzÅÌÀïµÄË®ÃæÉϵÎ1µÎ¸Ã¾Æ¾«ÓÍËáÈÜÒº£¬´ýÐÎ×´Îȶ¨ºó£¬½«²£Á§°å·ÅÔÚdzÅÌÉÏ£¬ÓòʱÊÃè»æ³öÓÍËáĤµÄÐÎ×´£®
C£®½«»ÓÐÓÍËᱡĤÂÖÀªµÄ²£Á§°å·ÅÔÚ×ø±êÖ½ÉÏ£¬°´²»×ã°ë¸öÉáÈ¥£¬¶àÓÚ°ë¸öµÄËãÒ»¸ö£¬Í³¼Æ³öÓÍËᱡĤÂÖÀªÖÐÓÐ430¸ö±ß³¤Îª1cmµÄÕý·½Ðθñ×Ó£®
¸ù¾ÝÒÔÉÏʵÑéÊý¾Ý¿ÉµÃ£º
£¨1£©Ò»µÎ¾Æ¾«ÓÍËáÈÜÒºÖк¬Óд¿ÓÍËáÌå»ýV=7.7¡Á10-12 m3£»£¨½á¹ûÈ¡2λÓÐЧÊý×Ö£©
£¨2£©ÓÉʵÑéÖª¸Ãͬѧ²âµÃµÄÓÍËá·Ö×ÓÖ±¾¶d=2¡Á10-10m£®£¨½á¹ûÈ¡1λÓÐЧÊý×Ö£©
·ÖÎö ½«ÅäÖƺõÄÓÍËá¾Æ¾«ÈÜÒº£¬Í¨¹ýÁ¿Í²²â³ö1µÎ´ËÈÜÒºµÄÌå»ý£®È»ºó½«1µÎ´ËÈÜÒºµÎÔÚÓÐðò×Ó·ÛµÄdzÅÌÀïµÄË®ÃæÉÏ£¬µÈ´ýÐÎ×´Îȶ¨ºó£¬½«²£Á§°å·ÅÔÚdzÅÌÉÏ£¬ÓòʱÊÃè»æ³öÓÍËáĤµÄÐÎ×´£¬½«»ÓÐÓÍËᱡĤÂÖÀªµÄ²£Á§°å·ÅÔÚ×ø±êÖ½ÉÏ£¬°´²»×ã°ë¸öÉáÈ¥£¬¶àÓÚ°ë¸öµÄËãÒ»¸ö£¬Í³¼Æ³öÓÍËᱡĤµÄÃæ»ý£®ÔòÓÃ1µÎ´ËÈÜÒºµÄÌå»ý³ýÒÔ1µÎ´ËÈÜÒºµÄÃæ»ý£¬Ç¡ºÃ¾ÍÊÇÓÍËá·Ö×ÓµÄÖ±¾¶£®
½â´ð ½â£º1µÎ¾Æ¾«ÓÍËáÈÜÒºµÄÌå»ýV1=$\frac{1}{260}$ mL£¬
ÓÉ´¿ÓÍËáÓëÈÜÒºÌå»ý±ÈΪ1£º500£¬¿ÉµÃ1µÎ¾Æ¾«ÓÍËáÈÜÒºÖк¬ÓÍËáµÄÌå»ýV2=$\frac{1}{260}$¡Á$\frac{1}{500}$mL=7.7¡Á10-12 m3
¶ø1µÎ¾Æ¾«ÓÍËáÈÜÒºÔÚË®ÃæÉÏÐγɵÄÓÍËᱡĤÂÖÀªÃæ»ýS=430¡Á10-4m2
ËùÒÔÓÍËá·Ö×ÓÖ±¾¶d=$\frac{{V}_{2}}{S}$=$\frac{7.7¡Á1{0}^{-12}}{430¡Á1{0}^{-4}}$m3=1.8¡Á10-10m¡¡
£¨ÓÉÓÚ½á¹û±£Áô1λÓÐЧÊý×Ö£¬ÔòΪ2¡Á10-10m£©
¹Ê´ð°¸Îª£º£¨1£©7.7¡Á10-12 £»£¨2£©2¡Á10-10£®
µãÆÀ ±¾ÌâÊÇÒÔÓÍËá·Ö×Ó³ÊÇòÐÍ·Ö²¼ÔÚË®ÃæÉÏ£¬ÇÒÒ»¸ö°¤Ò»¸ö£¬´Ó¶ø¿ÉÒÔÓÉÌå»ýÓëÃæ»ýÏà³ýÇó³öÓÍĤµÄºñ¶È£®
A£® | $\frac{£¨3-\sqrt{5}£©}{2}$R | B£® | $\frac{£¨3+\sqrt{5}£©}{2}$R | C£® | $\frac{£¨3-\sqrt{5}£©}{10}$R | D£® | $\frac{£¨3+\sqrt{5}£©}{10}$R |
A£® | ÖÜÆÚÏàͬ£¬µ«Ô˶¯Ê±¼ä²»Í¬£¬ËÙÂÊ´óµÄÔ˶¯Ê±¼ä³¤ | |
B£® | Ô˶¯°ë¾¶Ô½´óµÄÖÊ×ÓÔ˶¯Ê±¼äÔ½¶Ì£¬Æ«×ª½ÇԽС | |
C£® | ÖÊ×ÓÔڴų¡ÖеÄÔ˶¯Ê±¼ä¾ùÏàµÈ | |
D£® | Ô˶¯°ë¾¶²»Í¬£¬Ô˶¯°ë¾¶Ô½´óµÄÖÊ×ÓÏòÐļÓËÙ¶ÈÔ½´ó |
A£® | n4£¼n3 | |
B£® | Ö»Ôö´óÓû§×ܵç×èR£¬ÊäµçÏßµÄ×ܵç×èrÏûºÄµÄ¹¦Âʽ«¼õС | |
C£® | Ö»Ôö´óÓû§×ܵç×èR£¬µçѹ±íV2µÄʾÊý½«¼õС | |
D£® | µçѹ±íV1¡¢V2µÄʾÊýʼÖÕÏàµÈ |