题目内容
如右图所示是某电源的路端电压与电流的关系图象,下面结论正确的是( )
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241603578143531.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824160358048161.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241603578143531.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824160358048161.png)
A.电源的电动势为6.0 V |
B.电源的内阻为12Ω |
C.电源的短路电流为0.5A |
D.电流为0.3A时的外电阻是18Ω |
AD
试题分析:当电流为零时,电压为电源电动势,由此可知电源的电动势为6.0 V,A对;图像的斜率表示电源内阻
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824160358313815.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824160358469787.png)
点评:本题难度较小,熟练掌握闭合电路欧姆定律内容,理解图像的截距、斜率的物理意义
![](http://thumb2018.1010pic.com/images/loading.gif)
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