题目内容
用不同频率的光照射某金属,测量其反向遏止电压UC与入射光频率ν,得到UC-ν图象,根据图象求出该金属的截止频率νC= Hz,金属的逸出功W= eV,普朗克常量h= J·s.
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408242221353252592.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408242221353252592.png)
5.0×1014;2.0;6.4×10-34。
试题分析:根据UC-ν图象可知该金属的截止频率为:νC=5.0×1014Hz
根据爱因斯坦光电效应方程有:Ek=hν-W ①
又由光电子的最大初动能与遏止电压的关系有:Ek=eUC ②
由①②式联立解得遏止电压UC与入射光频率ν的关系方程为:UC=
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824222136464471.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824222138289480.png)
根据③式和图象可知,金属的逸出功为:W=2.0eV
普朗克常量为:h=
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824222139428973.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
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