题目内容
一宇宙空间探测器从某一星球的表面垂直升空,宇宙探测器升空到某一高度,发动机关闭,其速度随时间的变化如图所示.宇宙探测器在该星球表面所能达到的最大高度是 m.该星球表面的重力加速度大小是 m/s2.![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241539419262852.jpg)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241539419262852.jpg)
768m ![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824153941941490.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824153941941490.png)
试题分析:由题一可知,探测器在该星球表面先加速上升,再减速上升,最大速度
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824153942004575.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824153942113956.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824153942160945.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824153942222850.png)
由图可知减速阶段加速度
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824153942612890.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824153941941490.png)
点评:本题还可以用速度图线和时间轴围成的面积等于位移求上升的高度,图线的斜率绝对值为加速度大小。
![](http://thumb2018.1010pic.com/images/loading.gif)
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