题目内容
已知铜的摩尔质量M=63.5g/mol,铜的密度是ρ=8.9g/cm3,试估算铜原子的质量和铜原子的体积.已知NA=6.02×1023mol-1.
1.06×10-22g,1.2×10-23cm3
设想铜原子是一个个紧挨着排列的,利用阿伏加德罗常数即得.
铜原子的质量:
m=
=
=1.06×10-22g.
铜原子的体积:
v=
·
=
×
cm3=1.2×10-23cm3.
铜原子的质量:
m=
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115853446412.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115853462811.gif)
铜原子的体积:
v=
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115853478391.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115853493376.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115853509343.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115853524550.gif)
![](http://thumb2018.1010pic.com/images/loading.gif)
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