ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿ÊµÑé¿ÎÉÏͬѧÃÇÀûÓôòµã¼ÆʱÆ÷µÈÆ÷²Ä£¬Ñо¿Ð¡³µ×öÔȱäËÙÖ±ÏßÔ˶¯µÄ¹æÂÉ¡£ÆäÖÐһС×éµÄͬѧʹС³µ×öÔȼÓËÙÖ±ÏßÔ˶¯£¬²¢´ÓËù´ò¼¸ÌõÖ½´øÖÐÑ¡È¡ÁËÒ»Ìõµã¼£ÇåÎúµÄÖ½´ø£¬Èçͼ7Ëùʾ¡£Í¼ÖÐA¡¢B¡¢C¡¢D¡¢EÊÇ°´´òµãÏȺó˳ÐòÒÀ´ÎÑ¡È¡µÄ¼ÆÊýµã£¬ÔÚÖ½´øÉÏÑ¡¶¨µÄÏàÁÚÁ½¸ö¼ÆÊýµã»¹ÓÐËĸö´òÓ¡µãûÓл­³ö¡£

£¨1£©ÊµÑéÖУ¬³ý´òµã¼ÆʱÆ÷£¨º¬Ö½´ø£¬¸´Ð´Ö½£©Ð¡³µ£¬Æ½°å¡¢µ¼Ïß¼°¿ª¹ØÍ⣬ÔÚÏÂÃæµÄÒÇÆ÷ºÍÆ÷²ÄÖУ¬±ØÐèʹÓõÄÓÐ_____________¡££¨²»¶¨ÏîÑ¡Ôñ£©

A.µçѹºÏÊʵÄ50HzµÄ½»Á÷µçÔ´ B.µçѹ¿ÉÒÔµ÷µÄÖ±Á÷µçÔ´

C.¿Ì¶È³ß D.Ãë±í E.Ììƽ

£¨2£©´ÓÖ½´ø¿ÉÒÔ¿´³ö£¬¸Ã×öÔȼÓËÙÖ±ÏßÔ˶¯µÄС³µµÄÔ˶¯·½ÏòΪͼ7ÖеÄ__________¡£

A.´Ó×óÏòÓÒ B.´ÓÓÒÏò×ó

£¨3£©ÀûÓÃÖ½´øÅԱߵĿ̶ȳ߶Á³öÊý¾ÝDµãµÄλÖÃΪxD__________cm¡£

£¨4£©²¢¼ÆËã³ö£º£¨¼ÆËã½á¹û±£Áô2λÓÐЧÊý×Ö£©

¢Ù´òÖ½´øÉÏDµãʱС³µÔ˶¯µÄËٶȴóСvD=__________m/s£»

¢ÚС³µÔ˶¯¹ý³ÌÖеļÓËٶȴóСΪa=__________m/s2¡£

¡¾´ð°¸¡¿AC B 5.5 0.23 0.50

¡¾½âÎö¡¿

¸ù¾ÝÔȱäËÙÖ±ÏßÔ˶¯µÄÍÆÂÛ¹«Ê½¿ÉÒÔÇó³ö¼ÓËٶȵĴóС£¬¸ù¾ÝÔȱäËÙÖ±ÏßÔ˶¯ÖÐʱ¼äÖеãµÄËٶȵÈÓڸùý³ÌÖеÄƽ¾ùËٶȣ¬¿ÉÒÔÇó³ö´òÖ½´øÉÏDµãʱС³µµÄ˲ʱËٶȴóС¡£

£º£¨1£©ÊµÑéÖУ¬³ý´òµã¼ÆʱÆ÷£¨º¬Ö½´ø¡¢¸´Ð´Ö½£©¡¢Ð¡³µ¡¢Æ½°å¡¢Ìú¼Ų̈¡¢µ¼Ïß¼°¿ª¹ØÍ⣬ÔÚÏÂÁеÄÆ÷²ÄÖУ¬±ØÐëʹÓõÄÓеçѹºÏÊʵÄ50Hz½»Á÷µçÔ´¸ø´òµã¼ÆʱÆ÷¹©µç£¬ÐèÒªÓÿ̶ȳ߲âÁ¿¼ÆÊýµãÖ®¼äµÄ¾àÀë´¦ÀíÊý¾Ý£¬¹ÊÑ¡£ºAC£»

£¨2£©´ÓÖ½´ø¿ÉÒÔ¿´³ö£¬Î»ÒÆÔ½À´Ô½´ó£¬ËùÒÔ¸Ã×öÔȼÓËÙÖ±ÏßÔ˶¯µÄС³µµÄÔ˶¯·½ÏòΪ´ÓÓÒÏò×ó£¬BÕýÈ·¡£

£¨3£©¸ù¾Ý¿Ì¶È³ßµÄ¶Á·¨¶Á³ö

£¨4£©¸ù¾ÝÔȱäËÙÖ±ÏßÔ˶¯ÖÐʱ¼äÖеãµÄËٶȵÈÓڸùý³ÌÖеÄƽ¾ùËٶȣ¬ÓУº

ÓÉÌâÒâ¿ÉÖª£ºx1=1.00cm£¬x2=1.50cm£¬x3=2.00cm£¬x4=2.5cm

ÓÉ´Ë£¬T=0.1s£¬¸ù¾ÝÔȱäËÙÖ±ÏßÔ˶¯ÍÆÂÛ£¬¿ÉµÃ£º

¹Ê´úÈëÊý¾Ý½âµÃ£º .

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø