ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿(1)µç»ð»¨¼ÆʱÆ÷ÊÇÒ»ÖÖʹÓÃ______£¨Ìî¡°½»Á÷¡±»ò¡°Ö±Á÷¡±£©µçµÄ¼ÆʱÒÇÆ÷£¬¹¤×÷µçѹΪ220V£¬´òµãÖÜÆÚ0.02s¡£ÔÚ°²·ÅÖ½´øʱ£¬Òª¼ì²éÄ«·ÛÖ½ÅÌÊÇ·ñÒѾ­ÕýÈ·µØÌ×ÔÚ____ÉÏ£¬»¹Òª¼ì²éÄ«·ÛÖ½ÅÌÊÇ·ñ¼ÐÔÚÖ½´øÖ®¼ä¡£

(2)ÈçͼËùʾ£¬ÎªÒ»´ÎʹÓõç»ð»¨¼ÆʱÆ÷¼Ç¼С³µÔ˶¯Çé¿öµÄÖ½´ø£¬Í¼ÖÐA¡¢B¡¢C¡¢D¡¢E¡¢F¡¢GΪÏàÁڵļÆÊýµã£¬ÏàÁÚ¼ÆÊýµã¼äÓÐËĸö¼Æʱµãδ»­³ö¡£ÔòÀûÓÃÖ½´øÉϵÄÊý¾Ý¿ÉÇó³öС³µµÄ¼ÓËٶȴóСÊÇ________m/s2£®(±£ÁôһλÓÐЧÊý×Ö£©

¡¾´ð°¸¡¿½»Á÷ Ö½ÅÌÖá 0.5

¡¾½âÎö¡¿

(1)[1]µç»ð»¨´òµã¼ÆʱÆ÷ʹÓõÄÊǽ»Á÷µçÔ´£»

[2]ÔÚ°²·ÅÖ½´øʱ£¬Òª¼ì²éÄ«·ÛÖ½ÅÌÊÇ·ñÒѾ­ÕýÈ·µØÌ×ÔÚÖ½ÅÌÖáÉÏ£»

(2)[3]ÏàÁÚ¼ÆÊýµã¼äÓÐËĸö¼Æʱµãδ»­³ö£¬ËùÒÔÏàÁÚ¼ÆÊýµã¼äµÄʱ¼ä¼ä¸ôΪ

£¬

¸ù¾ÝÖð²î¹«Ê½¿ÉµÃ£º

£¬£¬£¬

Ôò¿ÉµÃ£º

£¬

´úÈëÊý¾Ý¿ÉµÃ£º

¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø