题目内容
(6分)在做“测定电池的电动势和内阻”实验时,某同学的线路连接如图甲所示。
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241547524224139.jpg)
(1)在答题卡的方框内画出与图甲对应的电路图;
(2)在图乙
-R坐标系中标出了该同学所测的实验数据点,试作出这些数据点的拟合直线,并读得该直线的纵轴截距为 A-1,求得其斜率为 V-1;
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241547525151129.png)
(3)求得电池的电动势是 V,内阻是 Ω。
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241547524224139.jpg)
(1)在答题卡的方框内画出与图甲对应的电路图;
(2)在图乙
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824154752437296.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241547525151129.png)
(3)求得电池的电动势是 V,内阻是 Ω。
(1)见解析(2)0.9 0.67(3)1.5(±0.1)(1分),1.4(±0.3)(1分)
试题分析:(1)电路图如图所示:
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241547526091480.jpg)
(2)纵截距表示:
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824154752687588.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824154752812557.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824154752921522.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824154753015509.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241547530933125.jpg)
点评:本题的关键是知道图像的斜率和纵截距表示的物理含义
![](http://thumb2018.1010pic.com/images/loading.gif)
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