题目内容
为了探究加速度与力的关系,某同学设计了如图所示的实验装置,带滑轮的长木板水平放置,板上有两个光电门相距为d,滑块通过细线与重物相连,细线的拉力F大小等于力传感器的示数.让滑块从光电门1由静止释放,记下滑到光电门2的时间t,改变重物质量来改变细绳拉力大小,重复以上操作5次,得到下列表格中5组数据.
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/2014082500341937317083.jpg)
(1)若测得两光电门之间距离为d=0.5m,运动时间t=0.5s,则a= m/s2;
(2)依据表中数据在坐标纸上画出a-F图象.
(3)由图象可得滑块质量m= kg,滑块和轨道间的动摩擦因数
= g=10m/s2)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/2014082500341937317083.jpg)
(1)若测得两光电门之间距离为d=0.5m,运动时间t=0.5s,则a= m/s2;
(2)依据表中数据在坐标纸上画出a-F图象.
(3)由图象可得滑块质量m= kg,滑块和轨道间的动摩擦因数
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003419388301.png)
(1)4.0 (2)图像如下 (3)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003419420475.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/2014082500341960731756.jpg)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003419404676.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003419420475.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/2014082500341960731756.jpg)
试题分析:(1)滑块在两个光电门之间从静止开始做匀加速直线运动,
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003419622668.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250034196691326.png)
(2)描点作图,注意根据牛顿第二定律合力即
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003419685673.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003419716407.png)
(3)根据牛顿第二定律可得
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003419732737.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003419716407.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003419778802.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003419404676.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250034198101045.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003419420475.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
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